<h3>Answer: 104 degrees</h3>
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Work Shown:
Inscribed angle theorem
arc measure = 2*(inscribed angle)
arc BCD = 2*(angle A)
arc BCD = 2*(97)
arc BCD = 194 degrees
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Break arc BCD into its smaller pieces
arc BCD = (minor arc BC) + (minor arc CD)
194 = (90) + (minor arc CD)
194-90 = minor arc CD
104 = minor arc CD
<h3>minor arc CD = 104 degrees</h3>
Answer:
2
Step-by-step explanation:
i dont know
The term that can be added to the list so the GCF is 12h3 would be 48h5.
The reason being is that 48 is first divisible by 12 and does not yield a fraction, and we can remove upon dividing 3 h's from this term as it contains a total of 5 h's.
Answer:
Step-by-step explanation:
Parameterize the ellipse as (acos∙,bsin∙). Take points P:=(acosp,bsinp) and Q:=(acosq,bsinq) on the ellipse, with midpoint M:=(P+Q)/2.
If |PQ|=2k, then
a2(cosp−cosq)2+b2(sinp−sinq)2=4k2
The coordinates of M are
xy==a2(cosp+cosq)b2(sinp+sinq)
192 minutes or 3 hours and 12 minutes
an hour is 60 minutes and 60 divided by five is 12 so i multiplied 12 by 4, which is 48 and multiplied 48 by 4 and i got my answer
