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Nikolay [14]
2 years ago
12

Julio caught 3 fish weighing a total of 23 1/2 pounds. One fish weighed 9 5/8 pounds and another weighed 6 1/4 pounds. How much

did the third fish weigh?
Mathematics
2 answers:
Airida [17]2 years ago
4 0
So we need to know what 23 1/2 + 9 5/8 + 6 1/4 is.
first, we need to make them into equivalent fraction. 
so...
23 1/2 can be 23 4/8
9 5/8 and
6 1/4 can be 6 2/8
let's add the whole numbers.
23 + 9 + 6 = 38
4/8 + 5/8 + 2/8 = 11/8 = 1 3/8
so 38 + 1 3/8 is 39 3/8
the answer is 39 3/8 pounds

DENIUS [597]2 years ago
4 0

Answer: The third fish weighs 7 5/8 pounds  

Step-by-step explanation:

Hi, to answer this question, first, we have to add the weights of both fishes.

9 5/8 + 6 1/4 = 9 5/8 + 6 2/8 = 15 7/8

Since the 3 fishes weight 23 1/2 pounds, we have to subtract the weight of the 2 fishes to the total.

23 1/2 -15 7/8= 23 4/8 - 15 7/8= 22 (8/8 +4/8) -15 7/8= 22 12/8 -15 7/8 = 7 5/8

The third fish weighs 7 5/8 pounds  

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<h3>How to find the z score (z statistic) for the sample mean?</h3>

If we're given that:

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  • Sample size = n
  • Population mean = \mu
  • Sample standard deviation = s

Then, we get:

z = \dfrac{\overline{x} - \mu}{s}

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Learn more about z statistic here:

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