Question

Ashley is choosing a popsicle from the freezer at random the probability of her picking a grape popsicle is 3/8 the probability of her picking a cherry popsicle is 1/3 in the rest of the Popsicles are orange what is the likelihood of Ashley selecting an orange popsicle

Answer 1

If an experiment has $N$ possible outputs, each with probability

$P_1,\ P_2,\ldots,\ P_N$

then the sum of all probabilities is always one:

$P_1 + P_2 + \ldots + P_N=1$

So, in your case, you have

$P(\text{grape}) + P(\text{cherry}) + P(\text{orange}) = 1$

plugging in the given values:

$\dfrac{3}{8} + \dfrac{1}{3} + P(\text{orange}) = 1 \iff \dfrac{17}{24} + P(\text{orange}) = 1$

we can deduce that

$P(\text{orange}) = 1-\dfrac{17}{24} = \dfrac{7}{24}$