(a) m<IJK = 90 since segment IK is a diameter
(b) KI = 10 since since LM = KM = KI = 5. The 3 segments are radii.
(c) EP * PL = OP * PF; EP = 2
(d) m<OFH = 178/2 = 89; inscribed angle is half measure of intercepted arc
25•15=365-50=315 so that is the answer
Answer:
4
Step-by-step explanation:
The given polynomial is :
p(x) = -2a⁴+8a³-9a
We need to find the degree of the polynomial.
Degree of the polynomial = degree is the value of the greatest exponent.
Here, the maximum value of the exponent is 4 in -2a⁴.
It means,
Degree of the polynomial = 4
