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Debora [2.8K]
3 years ago
7

Which values of a, b, and c represent the answer in simplest form? StartFraction 7 Over 9 EndFraction divided by StartFraction 4

Over 9 EndFraction = a StartFraction b Over c EndFraction a = 1, b = 4, c = 3 a = 1, b = 3, c = 4 a = 1, b = 63, c = 36 a = 1, b = 36, c = 63

Mathematics
2 answers:
Likurg_2 [28]3 years ago
8 0

Answer:

(A) is the correct answer

Step-by-step explanation:

1/6 stays the same but 3/5 canges to 5/3                                                                                                      

Annette [7]3 years ago
4 0

Answer:

Option 2 - a=1, b=3 and c=4

Step-by-step explanation:

Given : Expression  \frac{7}{9}\div\frac{4}{9}=a\frac{b}{c}

To find : Which values of a, b, and c represent the answer in simplest form ?

Solution :

Solving the expression first and then convert into mixed fraction.

\dfrac{7}{9}\div\dfrac{4}{9}=\dfrac{\frac{7}{9}}{\frac{4}{9}}

\dfrac{7}{9}\div\dfrac{4}{9}=\dfrac{7\times 9}{9\times 4}

\dfrac{7}{9}\div\dfrac{4}{9}=\dfrac{7}{4}

Writing \frac{7}{4} into mixed fraction by dividing the number,

\dfrac{7}{9}\div\dfrac{4}{9}=1\dfrac{3}{4}

On comparing, a=1, b=3 and c=4.

Therefore, option 2 is correct.

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Roll a pair of dice until it lands doubles.What is the probability you will get the first doubles within three rolls? (Correct t
mr Goodwill [35]

Answer:

Probability of rolling doubles in first three roles = 0.4124

Probability of it taking between 5 to 7 rolls = 0.1988

Step-by-step explanation:

Let's start by the total number of possible outcomes. This is 6 for one dice, and 6 for the other. So in total that's 6 x 6 = 36 different outcomes of the dice roll.

The number of ways we can roll a double is 6.

So the probability of rolling a double would be the number of ways to roll a double divided by the total possible outcomes.

This is : \frac{6}{36} = 0.1667

The probability of NOT rolling a double: 1 - 0.1667 = 0.8333

Since the probability of rolling a double is equal to 1 - probability of not rolling a double, we can answer the first question in the following way.

The probability of NOT rolling a double for the first THREE turns:               0.8333 x 0.8333 x 0.8333 = 0.5786

Probability of rolling a double in first THREE turns: 1 - 0.5786 = <u>0.4124</u>

The probability it will take between 5 to 7 rolls would be:

EQUATION 1: (probability of rolling no doubles in first 4 turns) x (probability of rolling a double in the next three turns)

Since we have already found the probability of rolling a double in three turns to be 0.4124, all we need to find is the probability of NOT rolling a double in the first four turns.

This is: 0.8333 * 0.8333 * 0.8333 * 0.8333 = 0.4822

Plugging this into EQUATION 1 we get: 0.4822 * 0.4124 = <u>0.1988</u>

5 0
3 years ago
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