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Debora [2.8K]
3 years ago
7

Which values of a, b, and c represent the answer in simplest form? StartFraction 7 Over 9 EndFraction divided by StartFraction 4

Over 9 EndFraction = a StartFraction b Over c EndFraction a = 1, b = 4, c = 3 a = 1, b = 3, c = 4 a = 1, b = 63, c = 36 a = 1, b = 36, c = 63

Mathematics
2 answers:
Likurg_2 [28]3 years ago
8 0

Answer:

(A) is the correct answer

Step-by-step explanation:

1/6 stays the same but 3/5 canges to 5/3                                                                                                      

Annette [7]3 years ago
4 0

Answer:

Option 2 - a=1, b=3 and c=4

Step-by-step explanation:

Given : Expression  \frac{7}{9}\div\frac{4}{9}=a\frac{b}{c}

To find : Which values of a, b, and c represent the answer in simplest form ?

Solution :

Solving the expression first and then convert into mixed fraction.

\dfrac{7}{9}\div\dfrac{4}{9}=\dfrac{\frac{7}{9}}{\frac{4}{9}}

\dfrac{7}{9}\div\dfrac{4}{9}=\dfrac{7\times 9}{9\times 4}

\dfrac{7}{9}\div\dfrac{4}{9}=\dfrac{7}{4}

Writing \frac{7}{4} into mixed fraction by dividing the number,

\dfrac{7}{9}\div\dfrac{4}{9}=1\dfrac{3}{4}

On comparing, a=1, b=3 and c=4.

Therefore, option 2 is correct.

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Answer:

a) P(5

And we can find this probability with this difference:

P(-1.90

And using the norma standard distribution or excel we got:

P(-1.90

b) P(X>6) =P(Z> \frac{6-7.37}{1.25}) = P(Z>-1.096)

And using the complement rule we got:

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(7.37,1.25)  

Where \mu=7.37 and \sigma=1.25

We are interested on this probability

P(5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(5

And we can find this probability with this difference:

P(-1.90

And using the norma standard distribution or excel we got:

P(-1.90

Part b

For this case we want this probability:

P(X>6)

And we can use the z score and we got:

P(X>6) =P(Z> \frac{6-7.37}{1.25}) = P(Z>-1.096)

And using the complement rule we got:

P(Z>-1.096) =1-P(Z

8 0
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Answer:

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