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Debora [2.8K]
2 years ago
7

Which values of a, b, and c represent the answer in simplest form? StartFraction 7 Over 9 EndFraction divided by StartFraction 4

Over 9 EndFraction = a StartFraction b Over c EndFraction a = 1, b = 4, c = 3 a = 1, b = 3, c = 4 a = 1, b = 63, c = 36 a = 1, b = 36, c = 63

Mathematics
2 answers:
Likurg_2 [28]2 years ago
8 0

Answer:

(A) is the correct answer

Step-by-step explanation:

1/6 stays the same but 3/5 canges to 5/3                                                                                                      

Annette [7]2 years ago
4 0

Answer:

Option 2 - a=1, b=3 and c=4

Step-by-step explanation:

Given : Expression  \frac{7}{9}\div\frac{4}{9}=a\frac{b}{c}

To find : Which values of a, b, and c represent the answer in simplest form ?

Solution :

Solving the expression first and then convert into mixed fraction.

\dfrac{7}{9}\div\dfrac{4}{9}=\dfrac{\frac{7}{9}}{\frac{4}{9}}

\dfrac{7}{9}\div\dfrac{4}{9}=\dfrac{7\times 9}{9\times 4}

\dfrac{7}{9}\div\dfrac{4}{9}=\dfrac{7}{4}

Writing \frac{7}{4} into mixed fraction by dividing the number,

\dfrac{7}{9}\div\dfrac{4}{9}=1\dfrac{3}{4}

On comparing, a=1, b=3 and c=4.

Therefore, option 2 is correct.

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"Two less than the total of a number and five"​
tino4ka555 [31]

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Step-by-step explanation:

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- Find the mean, median, mode, and range of the<br> data set.<br> {7, 3, 5, 4, 5}
noname [10]

Answer:

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Step-by-step explanation:

The median is 5. The mode is 5. The mean is 5.

6 0
3 years ago
he life of light bulbs is distributed normally. The variance of the lifetime is 625 and the mean lifetime of a bulb is 540 hours
almond37 [142]

Using the normal distribution, it is found that there is a 0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 540, \sigma = \sqrt{625} = 25

The probability of a bulb lasting for at most 569 hours is the <u>p-value of Z when X = 569</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{569 - 540}{25}

Z = 1.16

Z = 1.16 has a p-value of 0.877.

0.877 = 87.7% probability of a bulb lasting for at most 569 hours.

More can be learned about the normal distribution at brainly.com/question/24663213

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8 0
1 year ago
At this point, the writer wants to add a second policy
EleoNora [17]

The option B is correct option according to the passage which tells us that the In the United States, many individual states have also adopted legislation to eliminate, or at least reduce, phosphorous content in laundry detergents.

According to the statement

we have to find that the out of given options which is correct for replace the words in the passage.

So, For this purpose, we know that the

In the passage ,

Choices A, C, and D are incorrect because they do not mention legislation or policies that were adopted as a result of Schindler and Brunskill’s research on the effects of phosphates in laundry detergents.

And

Choice B is the best answer because it deals with a “policy outcome” related to the research. The adoption of legislation to reduce or eliminate phosphates in detergents is a policy outcome (a change in official policy concerning detergents) that was clearly informed by Schindler and Brunskill’s research.

So, The option B is correct option according to the passage which tells us that the In the United States, many individual states have also adopted legislation to eliminate, or at least reduce, phosphorous content in laundry detergents.

Learn more about passage here

brainly.com/question/25605883

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8 0
1 year ago
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