2x + 2y = 10
x + y = 5
x = 5 - y
Substitute for x in the other equation:-
(5 - y - 3)^2 + (y + 2)^2 = 16
(2 - y)^2 + (y + 2)^2 = 16
4 - 4y + y^2 + y^2 + 4y + 4 = 16
2y^2 + 8 = 16
2y^2 - 8 = 0
y^2 = 4
y = +/- 2
consider 2x + 2y = 10
when y = -2, 2x = 10 +4 giving x = 7
when y = 2, 2x = 10 - 4 giving x = 3
so solution is x = 7, y = -2 and x = 3, y=2.
Answer:
See below.
Step-by-step explanation:
The corners of the square are:
(-7, 6) which becomes (-6, 7)
(-2, 6) which becomes (-6, 2)
(-7, 1) which becomes (-1, 7)
(-2, 1) which becomes (-1, 2)
From the top left corner of the square, ABCD rotates to ACDB (clockwise), so Darla is correct.
The new square is in the same quadrant as the original, so quadrant 2.
Answer:
6
Step-by-step explanation:
Given,
...(i)
Differentiating w.r. to x.

From equation (1)

Now, at the point (1,3)


Answer:

And if we count the number of zeros before the number 7, we can rewrite the number like this:

We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
Step-by-step explanation:
For this case we have the following number given:

And if we count the number of zeros before the number 7, we can rewrite the number like this:

We cansolve this problem also counting the number of positions that we need to move the decimal point to the right in order to obtain the first number (7)
And the best option would be:
B. 7 x 10-7
Answer: x=75
Explanation:
x+10+x+20=180
combine like terms
2x+30=180
subtract 30 from each side
2x=150
divide each side by 2
x=75