Answer:
C. The distribution for town A is positively skewed, but the distribution for town B is symmetric.
Hope it helps you out!
Answer:
i don't know what exactly your question is but i believe this is the answer if you are trying to find f. f= -1/7g+5/7
Step-by-step explanation:
Easy peasy
the midpoint between
and
is
just average them
so given that (3,5) is the midpoint of (-4,5) and (x,y)
so by logic
and
times both sides by 2 for everybody
-4+x=6 and 5+y=10
add 4 to both sides for left one and minus 5 from both sides for right
x=10 and y=5
the coordinate of point C is (10,5)
the x coordinate is 10
We can say that exchanging one couple's ticket for an individual's ticket would increase the money in the cash box from 200 to 202 and it would result in an even number of couples tickets sold.
<u>Step-by-step explanation:</u>
Let the number of tickets sold to the individuals = s
Let the number of tickets sold to the couples = c
According to the question,
s + c = 46 ( Equation 1)
Since each individual's ticket is $6, the total amount of money made by selling tickets to individuals is 6s.
Similarly, since each ticket sold to couples is $8, the total amount of money made by selling tickets to couples is 8c.
So,
6 s + 8 c = 200 ( Equation 2)
On solving both the equations, we get
c = 38 and s = 8
Therefore, 8 tickets were sold to individuals and 38 tickets were sold to the couples.
Answer:
The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%
Step-by-step explanation:
For a normal random variable with mean Mu = 3.2 and standard deviation sd = 0.8 there is a distribution of the sample mean (MX) for samples of size 4, given by:
Z = (MX - Mu) / sqrt (sd ^ 2 / n) = (MX - 3.2) / sqrt (0.64 / 4) = (MX - 3.2) / 0.4
For a sample mean of 3.0, Z = (3 - 3.2) / 0.4 = -0.5
For a sample mean of 3.0, Z = (4 - 3.2) / 0.4 = 2.0
P (3.2 <MX <4) = P (-0.5 < Z <2.0) = 0.6687.
The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%
