Find the percent of increase of 17,500 to 21,000

Find the common ratio for 0.1,0.01,0.001

yulyashka [42]

The common ratio of the set of data is 0. 1

<h3>How to determine the common ratio</h3>

To determine the common ratio of a set of data, we have to

Divide the second term by the first term or
Divide the third term by the second term

For the given set of data

0.1,0.01,0.001

Let's divide the second term by the first term

= 0. 01/ 0. 1

= 0. 1

Thus, the common ratio of the set of data is 0. 1

Learn more about common ratio here:

brainly.com/question/1509142

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4 0

2 years ago

The plot below shows the graphs of three functions, f, g, and h, all of which determine the population of three different cities

monitta

So, here we have an exponential function.

Remember that an exponential function has the form:

$y=a(b)^x=a(1\pm\frac{r}{100})^x$

Where a represents an initial amount, and r is the rate of this amount to change. (Increase, or decrease).

So, given that the population of City A in 2000 was 40 thousand people and the population increased by 13% each year, we can say that

$\begin{gathered} a=40 \\ b=1+\frac{13}{100}=1.13 \end{gathered}$

So,

$f(x)=40(1.13)^x$

For city B:

$\begin{gathered} a=40 \\ b=1+\frac{16}{100}=1.16 \\ g(x)=40(1.16)^x \end{gathered}$

But something different happens with city C. This is not an exponential function, this is a linear function.

So,

$h(x)=40+10x$

7 0

1 year ago

Which of the following organizations monitors the work of independent auditors?

vitfil [10]

Answer:

<h2>C) Public Company Accounting Oversight Board</h2><h3>(PCAOB)</h3>

Step-by-step explanation:

The PCAOB is a nonprofit corporation established by Congress to oversee the audits of public companies in order to protect investors and further the public interest in the preparation of informative, accurate, and independent audit reports.

#hope it helps!

Answered by ReyvREYV111

7 0

2 years ago

Need help ASAP!!!!

geniusboy [140]

Answer:

C

Step-by-step explanation:

Because the number of x-values is the same as the number of
y-values. (What C Said)

7 0

3 years ago

What are the dimensions of a box that would hold 250 cubic centimeters of juice and have a minimum surface area

Elis [28]

The dimensions of a box that have the minium surface area for a given Volume is such that it is a cube. This is the three dimensions are equal:

V = x*y*z , x=y=z => V = x^3, that will let you solve for x,

x = ∛(V) = ∛(250cm^3) = 6.30 cm.

Answer: 6.30 cm * 6.30cm * 6.30cm. This is a cube of side 6.30cm.

The demonstration of that the shape the minimize the volume of a box is cubic (all the dimensions equal) corresponds to a higher level (multivariable calculus).

I guess it is not the intention of the problem that you prove or even know how to prove it (unless you are taking an advanced course).

Nevertheless, the way to do it is starting by stating the equations for surface and apply two variable derivation to optimize (minimize) the surface.

You do not need to follow with next part if you do not need to understand how to show that the cube is the shape that minimize the surface.

If you call x, y, z the three dimensions, the surface is:

S = 2xy + 2xz + 2yz (two faces xy, two faces xz and two faces yz).

Now use the Volumen formula to eliminate one variable, let's say z:

V = x*y*z => z = V /(x*y)

=> S = 2xy + 2x [V/(xy)[ + 2y[V/(xy)] = 2xy + 2V/y + 2V/x

Now find dS, which needs the use of partial derivatives. It drives to:

dS = [2y - 2V/(x^2)] dx + [2x - 2V/(y^2) ] dy = 0

By the properties of the total diferentiation you have that:

2y - 2V/(x^2) = 0 and 2x - 2V/(y^2) = 0

2y - 2V/(x^2) = 0 => V = y*x^2

2x - 2V/(y^2) = 0 => V = x*y^2

=> y*x^2 = x*y^2 => y*x^2 - x*y^2 = xy (x - y) = 0 => x = y

Now that you have shown that x = y.

You can rewrite the equation for S and derive it again:

S = 2xy + 2V/y + 2V/x, x = y => S = 2x^2 + 2V/x + 2V/x = 2x^2 + 4V/x

Now find S'

S' = 4x - 4V/(x^2) = 0 => V/(x^2) = x => V =x^3.

Which is the proof that the box is cubic.

3 0

3 years ago