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riadik2000 [5.3K]
2 years ago
12

Find the common ratio for 0.1,0.01,0.001

Mathematics
1 answer:
yulyashka [42]2 years ago
4 0

The common ratio of the set of data is 0. 1

<h3>How to determine the common ratio</h3>

To determine the common ratio of a set of data, we have to

  • Divide the second term by the first term or
  • Divide the third term by the second term

For the given set of data

0.1,0.01,0.001

Let's divide the second term by the first term

= 0. 01/ 0. 1

= 0. 1

Thus, the common ratio of the set of data is 0. 1

Learn more about common ratio here:

brainly.com/question/1509142

#SPJ1

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6 The temperature at Wonder Lake is 12°F. During a storm, the temperature changes by -26°F. What is the temperature after the st
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Answer:

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Step-by-step explanation:

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Eduardwww [97]

Answer:

15% = 3/20 = 0.15

1.25 =125% =5/4

12 3/8 = 12.375 = 1237.5%

Step-by-step explanation:

15% to fraction , then decimal ;

15\% = \frac{15}{100} \\Cross\:cancel\:common\:factor ; 5\\\\15\div 5 = 3\\100\div 5 = 20\\\\= \frac{3}{20}\\\\\frac{3}{20} = 0.15

1.25 to fraction , then percentage

1.25 = \frac{1.25}{1}  \times \frac{100}{100} \\\\1.25\times 100 =125\\1\times 100 = 100\\\\= \frac{125}{100} \\= \frac{5}{4} \\\\1.25\times 100\\= 125\%

12 3/8 to decimal then percentage

12\frac{3}{8} =\frac{99}{8} = 12.375\\\\12.375\times 100\\\\= 1237.5\%

5 0
3 years ago
1. Make sure your answers and work is SHOWN please and steps are in order.
JulijaS [17]

Been a while since I've done synthetic division.

1a. Let's assume that's supposed to be an equals sign

p(x) = 2x⁴ - 3x³ - 6x² + 5x + 6

possible rational roots have factors of 6 in the numerator and of 2 in the denominator.  We'll only worry about negative numerators.

Factors of six: 1,2,3,6, and we don't forget -1,-2,-3,-6

Factors of 2: 1,2

Possible rational roots:

(dividing by 1:) 1,-1,2,-2,3,-3,6,-6

(dividing by 2:) 1/2, -1/2  (2/2=1 is a duplicate, don't have to repeat it), 3/2, -3/2

Possible rational roots: 1,-1,2,-2,3,-3,6,-6, 1/2, -1/2, 3/2, -3/2

Synthetic division, trying x=1,

   1 | 2  -3  -6  5  6

             2  -1  -7  -2

       2    -1  -7  -2  4

Got a remainder of 4, so 1 isn't a root;

Trying x=-1  

-1 | 2  -3  -6  5  6

         -2   5  1  -6

     2  -5  -1  6  0

Zero remainder, found a root, x=-1.  This division says

(2x⁴ - 3x³ - 6x² + 5x + 6) / (x + 1) = 2x³ - 5x² - x + 6

Same set of rational roots on the cubic, we continue with x=2

2 | 2 -5 -1 6

         4 -2 -6

    2  -1 -3 0

Another zero remainder, x=2 is a root.  We're left with 2x² - x - 3 = 0, which factors as

(2x - 3)(x + 1) = 0

That's a second factor of x+1.  Our final factorization is

2x⁴ - 3x³ - 6x² + 5x + 6 = (x + 1)²(x-2)(2x - 3)

Fourth degree with a positive leading coefficient so goes to +infinity at both ends.  Double zero at x=-1, so it's tangent there, just touching the x axis, then down through x=3/2 and up through x=2.  

I'll leave the actually sketching and the other two polynomials to you -- that took some time.

4 0
3 years ago
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