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ArbitrLikvidat [17]

2 years ago

8

Choose the statement That is NOT ALWAYS true.

1 answer:

ivann1987 [24]2 years ago

4 0

The answer to your question is A

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Bob and Cheryl are taking a road trip that is 181.60 miles bob drove 1.4 of the total distances how many mile did bob drive

ankoles [38]

bob drove 1.4 miles out of 181.60 mile road trip

7 0

2 years ago

Which values are in the solution set of the compound inequality: 4(x+3)≤0 or 14x+1>3

ludmilkaskok [199]

Answer: 69

Step-by-step explanation: The hypotenuse of the atom and it’s vastly large core equals the square root of 420 divides by 5.4 which equals 69.

3 0

3 years ago

Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa

Nataly_w [17]

Answer:

The first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

coefficient of $x^{2}$ in the expansion of $(2+x - x^{2})^{6}$ = (240 - 192) = 48

Step-by-step explanation:

$(2+x)^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})$

= $6_{C_{0}} \times x^{0} \times 2^{6} + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4}$ + terms involving higher powers of x

= $64 + 192 \times x^{1} + 240 \times x^{2}$ + terms involving higher powers of x

so, the first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

Again,

$(2+x - x^{2})^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})$

Now, by inspection,

the term $x^{2}$ comes from k =5 and k = 6

for k = 5, the coefficient of $x^{2}$ is , $(-32) \times 6$ = -192

for k = 6 , the coefficient of $x^{2}$ is, $6_{C_{2}} \times 2^{4}$ = 240

so, coefficient of $x^{2}$ in the final expression = (240 - 192) = 48

3 0

2 years ago

How many births occur among women under the age of 20?

yaroslaw [1]

Answer:

what do you mean?

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

melomori [17]

Answer: $4\sqrt{3}$

Step-by-step explanation:

For this exercise it is important to remember the following:

$i=\sqrt{-1} \\\\i^2=-1$

Given the following expression:

$-2i\sqrt{-12}$

You can notice that the radicand (the number inside the square root) is negative. Therefore, in order to simplify the expression, you need to follow these steps:

1. Replace $\sqrt{-1}$ with $i$ and simplify:

$(-2i)(i)\sqrt{12}=-2i^2\sqrt{12}=-2(-1)\sqrt{12}=2\sqrt{12}$

2. Descompose 12 into its prime factors:

$12=2*2*3=2^2*3$

3. Substitute into the expression:

$=2\sqrt{2^2*3}$

4. Since $\sqrt[n]{a^n}=a$ , you can simplify it:

$=(2)(2)\sqrt{3}=4\sqrt{3}$

4 0

2 years ago