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alekssr [168]
3 years ago
5

The perimeter of a rectangle is at most 80 inches. The length of the rectangle is 25 inches. The inequality 80-2w>50 can be u

sed to find w, the width of the rectangle in inches. Solve the inequality and iinterpret the solution. How will the solution change if the width must be at least 10 inches and a whole number?
Mathematics
1 answer:
andre [41]3 years ago
5 0
W is less than or equal to 15
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tatyana61 [14]

Answer:

(a)g(n)=0.05\cdot 2^n

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Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43

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Answer:

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