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Elena L [17]
2 years ago
5

The scale in the drawing is 2 cm : 5 m. Select from the drop down the correct numbers into the boxes to give the length, width,

and area of the actual room.
Mathematics
1 answer:
Gelneren [198K]2 years ago
7 0

The length, width, and area will be 25m, 15m, and 375m².

<h3>How to calculate the area?</h3>

From the information given, the scale in the drawing is 2cm : 5m and the length and width are given as 10cm and 6cm respectively.

Length = 10cm = 10 × 2.5 = 25m

Width = 6cm = 6 × 2.5m = 15m

Area = Length × Width

Area = 25 × 15

Area = 375m²

Therefore, the area is 375m².

Learn more about area on:

brainly.com/question/25292087

#SPJ1

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Please solve this in 2 parts as stated... thank you!
fredd [130]

Solve the equation we have that:

a. S = 3V²/ 4

b. S = 108 feet

<h3>How to solve the parameters?</h3>

We have the equation to be;

V = 2√3S

Where;

  • V is the speed
  • S is the length

Let's make S the subject from the formula, divide both sides by 2√2S = v/ 2. Take square of both sides:

(\sqrt{3S} )^2 = \frac{V^2}{4}\\3S = \frac{V^2}{4}

Now we need to divide both sides by three:

S = 3V²/ 4

b. If v = 12miles per hour, substituting in the equation found earlier:

S = 3 (12²)/ 4

S= 432/ 4

S = 108 feet

Thus, the formula for the length is S = 3V²/ 4

Learn more about speed here: brainly.com/question/7359669

#SPJ1

4 0
1 year ago
What is the value of the 8 in the number 2.387
tamaranim1 [39]

Answer:

Step-by-step explanation:

If the point represents decimal, the position of number 8 is  

hundredth.

But if  represents Thousands the position of number 8  is  

tens

6 0
3 years ago
Read 2 more answers
The sum of a number and twenty is greater than four times the number decreased by one
Virty [35]

is that the question?

7 0
3 years ago
Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12
Afina-wow [57]
Hey there, hope I can help!

\frac{1}{4}\csc \left(2\pi t\right)\cot \left(2\pi t\right)dt\frac{1}{12}

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}\cdot \frac{d}{e}=\frac{a\:\cdot \:b\:\cdot \:d}{c\:\cdot \:e} \ \textgreater \  \frac{1\cdot \:1\cdot \:dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \  \frac{dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:12=48 \ \textgreater \  \frac{dt}{48}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \  \frac{dt\csc \left(2\pi t\right)\cot \left(2\pi t\right)}{48}

Hope this helps!
5 0
3 years ago
A transformation T : (x, y) → (x + 3, y + 1). Find the preimage of the point (4, 3) under the given transformation. (7, 4) (1, 2
motikmotik

Answer:

(1, 2)

Step-by-step explanation:

Remember that the final shape and position of a figure after a transformation is called the image, and the original shape and position of the figure is the pre-image.

In our case, our figure is just a point. We know that after the transformation T : (x, y) → (x + 3, y + 1), our image has coordinates (4, 3).

The transformation rule T : (x, y) → (x + 3, y + 1) means that we add 3 to the x-coordinate and add 1 to the y-coordinate of our pre-image. Now to find the pre-image of our point, we just need to reverse those operations; in other words, we will subtract 3 from the x-coordinate and subtract 1 from the y-coordinate.

So, our rule to find the pre-image of the point (4, 3) is:

T : (x, y) → (x - 3, y - 1)

We know that the x-coordinate of our image is 4 and its y-coordinate is 3.

Replacing values:

                (4 - 3, 3 - 1)

                (1, 2)

We can conclude that our pre-image is the point (1, 2).

6 0
3 years ago
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