Question

A spinner is divided into four equal sections that are numbered 2, 3, 4, and 9. The spinner is spun twice. How many outcomes have a product less than 20 and contain at least one even number?

Answer 1

Answer with Step-by-step explanation:

On spinning the spinner twice,we have 16 different outcomes:.

We write the outcomes with their product:

                      Product

2    2                   4

2    3                   6

2    4                  8

2    9                  18

3    2                   6

3    3                   9

3    4                   12

3    9                   27

4    2                   8

4    3                    12

4    4                   16

4    9                   36

9    2                    18

9    3                    27

9    4                    36

9    9                    81

outcomes have a product less than 20 and contain at least one even number are in bold letters.

Hence, outcomes have a product less than 20 and contain at least one even number are:

10

Answer 2

Answer:

7

Step-by-step explanation:

Considered that the spinner is spun twice, we have 16 different combinations:

2 2

2 3

2 4

2 9

3 2

3 3

3 4

3 9

4 2

4 3

4 4

4 9

9 2

9 3

9 4

9 9

I have written in bold the combinations that contain at least one even number: there are 12 of them.

Now we have to check the product of each of these combinations:

2 x 3 = 6

2 x 9 = 18

3 x 2 = 6

3 x 3 = 9

3 x 4 = 12

3 x 9 = 27

4 x 3 = 12

4 x 9 = 36

9 x 2 = 18

9 x 3 = 27

9 x 4 = 36

9 x 9 = 81

Here I have written in bold the combinations that have a product less than 20: there are 7 of them.

So, 7 out of 16 outcomes have a product less than 20 and contain at least one even number.