Answer:
0, for q ≠ 0 and q ≠ 1
Step-by-step explanation:
Assuming q ≠ 0, you want to find the value of x such that ...
q^x = 1
This is solved using logarithms.
__
x·log(q) = log(1) = 0
The zero product rule tells us this will have two solutions:
x = 0
log(q) = 0 ⇒ q = 1
If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to <em>any</em> power.
_____
<em>Additional comment</em>
The applicable rule of logarithms is ...
log(a^b) = b·log(a)
F ( x ) = ( 3 x + 6 ) ( 3 x - 6 ) / ( 3 x + 6 ) = 3 x - 6
and for domain : 3 x + 6 ≠ 0
3 x ≠ - 6
x ≠ - 2
anwser graph of 3 x - 6, with discontinuity at - 2
Hello there! Emperor Constantine the Great, otherwise known as Constantine I, legalized Christianity in the Roman Empire.
Constantine I stopped the bans on Christianity in an effort to gain supporters of his control/power. Hope this helps!
Answer:
A system of the equation of a circle and a linear equation
A system of the equation of a parabola and a linear equation
Step-by-step explanation:
Let us verify our answer
A system of the equation of a circle and a linear equation
Let an equation of a circle as
..........(1)
Let a liner equation Y = x ............(2)
substitute (2) in (1)

so Y =
so the two solution are (
)
A system of the equation of a parabola and a linear equation
Let equation of Parabola be 
and linear equation y = x
substitute

Y = 0,1
so the two solutions will be (0,0) and (1,1)
Step-by-step explanation:
<u>From the figure</u> :
Cos 57° = 19.3 / AB
AB = 19.3 / 0.54
<u>AB = 35.74 cm</u>