3 years ago

Find the equation of this line

Mathematics

2 answers:

olasank [31]3 years ago

7 0

I needed help on that one too

Snowcat [4.5K]3 years ago

3 0

Y=-1/2+1
Hope this helps :)

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If f (x)=1/3(6)x what is f(2)

Ksju [112]

Answer: 4

Step-by-step explanation:

f (x)=1/3*(6)*x

f (2)=1/3*(6)*2=2*2=4

6 0

3 years ago

Find and simplify the difference quotient of the form<img src="https://tex.z-dn.net/?f=%5Cfra%5Cfrac%7Bf%28x%29-f%28a%29%7D%7Bx-

Ilia_Sergeevich [38]

Answer: 3x + 13

Step-by-step explanation:

$f(x)=3x^2+x\\f(a)=3a^2+a\\f(4)=3*4^2+4=52\\\\f(x)-f(4)=3x^2+x-52=(x-4)(3x+13)\\\\\dfrac{f(x)-f(4)}{x-4} =\dfrac{3x^2+x-52}{x-4} \\\\if\ x \neq 4\ then \\\\\dfrac{f(x)-f(4)}{x-4} =\dfrac{(x-4)(3x+13)}{x-4} \\\\=3x+13\\$

6 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST! NEED ANSWER FAST!

yuradex [85]

Answer:

x= 251

Step-by-step explanation:

300x= 190x + 27,610

300x-190x= 27,610

110x= 27610

x= 27610/110

x= 251

3 0

3 years ago

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

$\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

$\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)$

$f'(y)=0\implies f(y)=C$

$\implies F(x,y)=x^2y^3+\ln(x+y^2)=C$

With $y(1)=2$ , we have

$8+\ln9=C$

$\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}$

8 0

3 years ago

Can u solve this for me??

dangina [55]

Answer:

19 lawns

Step-by-step explanation:

well 64.99 is about $65

so you would need to mow atleast 19 lawns (this does not included tax XD)

3 0

3 years ago

Find the equation of this line​

Find the equation of this line