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Ainat [17]
4 years ago
12

Find C and round to the nearest tenth.

Mathematics
2 answers:
GalinKa [24]4 years ago
8 0

Answer:

29.4 degrees

Step-by-step explanation:

i divided sin by 55 degrees

Yuki888 [10]4 years ago
4 0
We know all the side lengths so can use law of cosines. a=90, b=55, and c=50.
2500=8100+3025-2(90)(55)cos(C)
cos(C)=.8712
C=arccos(.8712)=29.4 degrees
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Ilya [14]

Answer:

The original side length of the square was 9 ft

Step-by-step explanation:

Consider that the square was initially of side length "x" (our unknown). Then the sides were all increased by 5 ft, and now the perimeter (addition of all four sides) of the square render 56 ft.

Let's write an equation that represents the addition of the four sides of this new rectangle, and set it equal to 56 ft. Then solve for the unknown "x":

(x+5)+(x+5)+(x+5)+(x+5)=56\\x+x+x+x+5+5+5+5=56\\4x+20=56\\4x=56-20\\4x=36\\x=9

Therefore, the original side of the square was 9 ft.

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3 years ago
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Consider the following equations. f(x)= x^3 +3x^2 -2x+1 g(x)= x^2-5x+4 Approximate the solution to the equation f(x) = g(x) usin
Masja [62]

Answer:

A. x = 11/16

Step-by-step explanation:

For the purpose here, it is convenient to rearrange the equation to f(x) -g(x) = 0. We know the root will be in the interval [0, 1] because (f-g)(0) = -3 and (f-g)(1) = +3. At each iteration, we evaluate (f-g)(x) at the midpoint of the interval to see which of the interval end points can be moved and still bracket the root.

Using the bisection method starting with the interval [0, 1] we find f(1/2)-g(1/2) < 0, so we can move the interval limits to [1/2, 1].

For the next iteration, we find f(3/4) -g(3/4) > 0, so we can move the interval limits to [1/2, 3/4].

For the third iteration, we find f(5/8) -g(5/8) < 0, so we can move the interval limits to [5/8, 3/4].

Then the root is approximately the middle of that interval:

x ≈ (5/8 +3/4)/2 = 11/16

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This value of x is 0.6875. The root is closer to 0.639802004233. The bisection method takes about 3 iterations for each decimal place of accuracy. Other methods can nearly double the number of accurate decimal places on each iteration.

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3 years ago
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Naily [24]
If two figures are similar, the corresponding side ratios are equal.
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Have an awesome day! :)

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3 years ago
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Me ayudan por favor??<br> ¿Qué tres números consecutivos suman 156?
dolphi86 [110]
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<em>espero</em><em> </em><em>que</em><em> </em><em>esto</em><em> </em><em>te</em><em> </em><em>ayude</em><em> </em><em>:</em><em>)</em>

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I think it best to actually do the problem to determine the correct answer.

Clearing out the fractions, I found that

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