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Makovka662 [10]
3 years ago
11

Alana incorrectly simplified the expression (-14a + 12) - (-10a + 13) as -24a + 25 describe her error

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
7 0

Answer:

The answer should be -4a-1. This is because you have to open the box.

-(-10a+13)

Two negatives become positive so she should have had -14+10 to make -4 and 12-13 to make -1. A negative and positive together, the negative always wins so that why you subtract.

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DIA [1.3K]

Answer:

x²+y²+4x-21=0

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Whoever answers gets brainliest and 100 points help
LenaWriter [7]

Answer:

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8 0
3 years ago
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How do i solve for x? *you have to show work*
eduard
1) Factor the equation first:

2e^{2x} + 4xe^{2x} = 0
e^{2x}(2 + 4x) = 0

So either e^{2x} = 0 or 2 + 4x = 0. But e^{2x} = 0 can never equal 0! So, we only need to solve for the second equation:

2 + 4x = 0
\bf x = {-\frac{1}{2}}

2) First, single out the term with the exponent:

2 + 3(4^{2x - 1}) = 43
3(4^{2x - 1}) = 41
4^{2x - 1} = \frac{41}{3}

Now, taking the log base 4 of each side gives us

2x - 1 = \log_4 \frac{41}{3}

and we can now solve for x:

2x - 1 = \log_4 \frac{41}{3}
2x = 1 + \log_4 \frac{41}{3}
2x = \log_4 4 + \log_4 \frac{41}{3}
2x = \log_4 \frac{164}{3}
x = \frac{1}{2} \log_4 \frac{164}{3}
x = \log_4 \sqrt \frac{164}{3}
\bf x = \log_4 2 \sqrt \frac{41}{3}
8 0
3 years ago
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