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3 years ago

Helppppppppppppppppppppppppp

Mathematics

2 answers:

Nezavi [6.7K]3 years ago

7 0

Answer:

It should be A, $12.75

Step-by-step explanation: Add 10.5+10.5+10.5+4.5+4.5+6.75= $47.25, subtract 60-47.25= $12.75

NARA [144]3 years ago

4 0

It’s would be 12.75 because when you add the 1 grandstand, 2 bleachers and the 3 box seats you get 47.25 and 60-47.25=12.75.

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Hello everyone can you answer this for me? What is A in the equation attached? Please and thank you.

lapo4ka [179]

Answer:

a = 6

Step-by-step explanation:

Hello!

Solve:

4(3a - 4) = 56
3a - 4 = 14 (factoring out 4)
3a = 18 (adding 4 to both sides)
a = 6 (dividing by 3)

Another way:

4(3a - 4) = 56
12a - 16 = 56 (distributive property)
12a = 72 (moving like terms)
a = 6 (dividing by 12)

Distributive Property of Multiplication:

The process of distributing the outside factor to the terms in the parenthesis.

Example:

$4(3a - 4)\\\\4(3a) - 4(4)\\\\12a - 16$

7 0

3 years ago

Read 2 more answers

Which function represents a line with a slope of −4 and a y-intercept of −2?

NNADVOKAT [17]

Answer:

y=-4x-2 so c

Step-by-step explanation:

the slope is always gonna be the number that is attached to the x

5 0

3 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

How do you find the quadratic equation for the roots 3 and 17?

Naily [24]

The roots are 3 and 17 so the distributed equation is

(x-3)(x-17)

distribute

x²-3x-17x+51

x²-20x+51

I hope I've helped!

6 0

3 years ago

What is x^2+11x=0? im confused on what my “c value” is.

jeka94

Answer:

c=0

Step-by-step explanation:

x² + 11x + 0 = y

x² + 11x + 0 = 0

U already know that y=0 by looking at the equations above,

But your worksheet never state "c", so we will take that c is 0 (look at the equations above.)

So c is just 0.

7 0

3 years ago