| u | = √(2² + (-1²)) = √5
| v | = √ ( 1² + (-8)² = √65
cos (u,v) = ( u * v ) / (| u | * | v |) =
(2 * 1 + ( -1 ) * ( - 8 )) / √5 √ 65 = (2 + 8) / √5 √65 = 10 / (√5 √ 65 )
The length of a larger diagonal:
d 1² = | u |² + 2 |u| |v| + | v |² = 5 + (2 √5 √65 * 10 / √5 √65 )+65
d 1² = 70 + 20 = 90
d 1 = √ 90 = 3√10
d 2² = 70 - 20 = 50
d 2 = √50 = 5√2
Answer:
The lengths of the diagonals are: 3√10 and 5√2 .
Answer:
for question #1) 6 times n + 12 = 60
Step-by-step explanation:
it works trust me
ps. im in high school in a GT math class
Answer:
huh what does this mean
Step-by-step explanation:
Answer:
Area of shaded region ≈ 192.42
Step-by-step explanation:
21/2 = radius
radius = 10.5 m
A = πr squared
Area of shaded region≈346.36
10.5 - 3.5 = 7
Area of unshaded region ≈ 153.94
346.36 - 153.94 = 192.42
