Answer:
its easy
Explanation:
there are are 5 main rules
in binary there are 2 number 0 and 1
0 + 0 = 0
0 + 1 = 1
1+0=1
1+1=0 carry 1
e . g
1 1 1
1 0 1 0 1 0
+ 1 1 0 0 1 0
-------------------------
1 1 1 1 1 0 0
*in bold are the ones that you need to carry.
in decimal there are 10 possible numbers 0- 9
when you do 1 + 9 it becomes 10, this can be done easily, however if you do 1 + 9 in a table like above, you will get 0 for the first column and you will carry 1 to the next column .
in binary is the same idea but using on 2 numbers 1 and 0
e.g
1
1
+ 9
----------
1 0
*in bold are the ones that you need to carry.
hope it helps and good luck in your exam.
Answer:
DHCP is the dynamic host configuration protocol that enable the server for assigning the IP address to the computer. It is basically used to provide automatic IP addresses within the network. It is basically used to configure the default gateway and provide the DNS server data in the device.
The optional parameter when configuring DHCP are:
- Sub-net mask
- Router
- Domain server
- Broadcast address
- Host name
Answer: TDMA(Time division multiple access)
Explanation: Time-division multiple access is the method that is used by GSM(Global system for mobile communication) usually for the separation process of the data.It is a way in which a same frequency is shared by different time slots of signal.It has high flexibility and so thus is helpful for the GSM network and provides easy services of division.It divides the data according to the time period slots in a GSM network.
Answer:
Explanation:
The following code is written in Java and it uses nested for loops to create the array elements and then the same for loops in order to print out the elements in a pyramid-like format as shown in the question. The output of the code can be seen in the attached image below.
class Brainly {
public static void main(String[] args) {
int jagged[][] = new int[5][];
int element = 1;
for(int i=0; i<5; i++){
jagged[i] = new int[i+1]; // creating number of columns based on current value
for(int x = 0; x < jagged[i].length; x++) {
jagged[i][x] = element;
element += 1;
}
}
System.out.println("Jagged Array elements are: ");
for ( int[] x : jagged) {
for (int y : x) {
System.out.print(y + " ");
}
System.out.println(' ');
}
}
}
