You can join tables by using a condition in the "where" clause.
Answer:
import java.util.Scanner;
import java.util.Arrays;
import java.util.Random;
public class Main {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.print("Enter low: ");
int low = scan.nextInt();
System.out.print("Enter high: ");
int high = scan.nextInt();
scan.close();
int rndnumbers[] = new int[10];
Random r = new Random();
for(int i=0; i<rndnumbers.length; i++) {
rndnumbers[i] = r.nextInt(high-low+1) + low;
}
for(int i=0; i<rndnumbers.length; i++) {
System.out.printf("%d: %d\n", i, rndnumbers[i]);
}
}
}
Answer:
The correct answer to the following question will be "Θ(n2)
". The further explanation is given below.
Explanation:
If we're to show all the objects that exist from either the first as well as the second vector, though not all of them, so we'll have to cycle around the first vector, so we'll have to match all the objects with the second one.
So,
This one takes:
= 
And then the same manner compared again first with the second one, this takes.
=
Therefore the total complexity,
= Θ(n2)
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The German mathematician & physicist ”Carl Friedrich Gauss”
Born: April 30, 1777, Brunswick, Germany
Died: February 23, 1855, Göttingen, Germany
