Answer:
First side is 19, second side is 38 and third side, the longest is 43.
Step-by-step explanation:
Let's call the first side a.
The second side, being twice as long as the first, is 2a.
The third side is 2a+5.
The equation is:
a+2a+2a+5=100, since 1 metre is 100 centimetre.
5a+5=100
5a=95
a=19
First side is 19, second side is 38 and third side, the longest is 43.
9514 1404 393
Answer:
3.77
Step-by-step explanation:
For daily compounding, the balance is ...
A = P(1 +r/365)^n . . . . principal P invested at annual rate r for n days
A = 1000(1 +0.055/365)^25 ≈ 1003.77
Of this amount, 1000 is the original principal. The difference is the interest.
The interest earned is 3.77.
Answer: the integers are 6 and 23
Step-by-step explanation:
Let x represent one of the integers.
Let y represent the other integer.
The product of the integers is 138. This means that
xy = 138 - - - - - - - - - -1
One of the integers is seven less than five times the other integer. This means that
x = 5y - 7
Substituting x = 5y - 7 into equation 1, it becomes
y(5y - 7) = 138
5y² - 7y = 138
5y² - 7y - 138 = 0
5y² + 23y - 30y - 138 = 0
y(5y + 23) - 6(5y + 23)
y - 6 = 0 or 5y + 23 = 0
y = 6 or y = - 23/5
The only possible value of y is 6
x = 138/y = 138/6
x = 23
For
ax+by=c
slope=-a/b
we have
-6x+1y=-4
slope=-6/-1=6
slope is 6
yint is where x=0
-6(0)+y=-4
0+y=-4
y=-4
yint is at y=-4 or (0,-4)
Answer:
0.025 = 2.5% probability that a given class period runs between 51.5 and 51.75 minutes.
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X lower than x is between c and d is given by the following formula
For this problem, we have that:
. So
0.025 = 2.5% probability that a given class period runs between 51.5 and 51.75 minutes.
