Question

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 47.047.0 and 57.057.0 minutes. Find the probability that a given class period runs between 51.551.5 and 51.7551.75 minutes.

Answer 1

Answer:

0.025 = 2.5% probability that a given class period runs between 51.5 and 51.75 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is between c and d is given by the following formula

$P(c \leq X \leq d) = \frac{d - c}{b-a}$

For this problem, we have that:

$a = 47, b = 57, c = 51.5, d = 51.75$. So

$P(c \leq X \leq d) = \frac{d - c}{b-a}$

$P(51.5 \leq X \leq 51.75) = \frac{51.75 - 51.5}{57 - 47} = 0.025$

0.025 = 2.5% probability that a given class period runs between 51.5 and 51.75 minutes.