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Mandarinka [93]
3 years ago
11

Which expressions are equivalent to this exponential expression

Mathematics
1 answer:
wariber [46]3 years ago
3 0

Answer:

\dfrac{5^4\times 5^{-2}}{5^3}=\dfrac{1}{5}

A is correct.

Step-by-step explanation:

Given: \dfrac{5^4\times 5^{-2}}{5^3}

We are given a exponential expression and to simplify it.

Exponent Law:

  • Product Rule: a^m\times a^n=a^{m+n}
  • Quotient Rule: a^m\div a^n=a^{m-n}
  • Negative Exponent:  a^{-m}=\dfrac{1}{a^m}

\Rightarrow \dfrac{5^4\times 5^{-2}}{5^3}

Using Quotient rule

\Rightarrow 5^{4-3}\times 5^{-2}

\Rightarrow 5^{1}\times 5^{-2}

Using Product Rule

\Rightarrow 5^{1-2}

\Rightarrow 5^{-1}

Using Negative exponent law

\Rightarrow \dfrac{1}{5}

Therefore,  \dfrac{5^4\times 5^{-2}}{5^3}=\dfrac{1}{5}

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Answer:

79. [7, 12], [1, 6]

80. The total revenue in the month of May is $11,575

81. The total revenue in the month of November is $4,630

82. Values obtained from the model and actual values are almost the same, so the given model is precise.

Step-by-step explanation:

79.

The domain of a function is the set of x-values that we are allowed to plug into our function.

The graph below represents f(x),

the graph that the domain of the first part of the function is [7,12]. The domain of the second part of the function is [1,6]. The solution is:

f(x)=\left \{ {{-1.97x+26.3, 7 \leq x \leq 12} \atop {0.505x^{2} -1.47x+6.3, 1 \leq x \leq 6}} \right. \\\\

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1 ≤ 5 ≤ 6, so we'll plug the value 5 in the function f(x) = 0.505x² - 1.47x + 6.3

f(x) = y = (0.505)(5)² - 1.47(5) + 6.3

f(x) = y = (0.505)(25) - 7.35 + 6.3

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For x=5 which represents 5th month May, we got y=11.575

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7 ≤ 11 ≤ 12, so we'll plug the value 11 in the function f(x) = -1.97x + 26.3

f(x) = − 1.97(11) + 26.3

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For x=11 which represents 11th month November, we got y=4.630 Therefore, the total revenue in the month of November is 4.630 thousands dollars, 4,630 dollars.

82.

Values obtained from the model are y=11.575 (x=5) and y=4.630 (x=11). Actual data values are y=11.5 (x=5) and y=4.4 (x=11)

By comparing these values, we can conclude that the model is precise, because these values are almost the same.

Learn more about Piecewise Functions here: brainly.com/question/13882670

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