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3 years ago

You are to find the maximum and minimum value of the objective function in the domain

1 answer:

4 0

If f is differentiable at c and f′(c) = 0, then we call c a critical point or stationary point of f. A point c at which the derivative of f is not defined is called a singular point of f.

Thus we know that the candidates for the location of the extreme values of a continuous function on a closed interval fall into three categories: (a) endpoints of the interval, (b) critical points, and (c) singular points. To determine the extreme values of such a function f, we identify all these points, evaluate f <span>at each one, and identify the largest and smallest values. </span>

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HELLLLLLLLLLPPPPPPPPPPPPPPPP NO LINKS PLZZZZZZZZZZ

melisa1 [442]

Answer:

I cant see any pictures?

Step-by-step explanation:

7 0

3 years ago

Can anyone help me please?

Tems11 [23]

The first one

Step-by-step explanation:

the other ones are not statistical

I hope this helps!

6 0

3 years ago

Read 2 more answers

. Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P. Side QR = 17m, diagonal QS

trapecia [35]

Answer:

495 meter²

Step-by-step explanation:

In the given kite QRST,

PQ = PS = 15 meter

QR = 17 meter

We have to find the area of the kite.

Since kite is in the form of a rhombus.

and rhombus is = $\frac{1}{2}$ (Diagonal QS) × (Diagonal RT)

In Δ QRP,

17² = 15² + RP²

$\sqrt{17^{2}-15^{2}} = RP$

$RP=\sqrt{289-225}$

= √64 = 8 meters.

So RT = RP + PT = 8 + 25 = 33 meter.

Now area of kite = $\frac{1}{2}$ (30) (33) = 495 meter²

6 0

3 years ago

Is √8 a rational or irrational number

yawa3891 [41]

Answer:

irrational

Step-by-step explanation:

irrational because there will still be a 2 under the root when you simplify to 2√2

3 0

3 years ago

Solve the system (x-1)²+(y-2)²=2² and y=2x+2.

Likurg_2 [28]

Answer:

(x, y) = (-0.6, 0.8) or (1, 4)

Step-by-step explanation:

Use the second equation to substitute for y in the first.

(x -1)² +((2x +2) -2)² = 4

x -2x +1 + 4x² = 4 . . . . . . . eliminate parentheses

5x² -2x -3 = 0 . . . . . . . . . . subtract 4, collect terms

Now we can rearrange the middle term to ease factoring by grouping.

(5x² -5x) +(3x -3) = 0

5x(x -1) +3(x -1) = 0

(5x +3)(x -1) = 0

The values of x that make these factors zero are ...

x = -3/5, x = 1

The corresponding values of y are ...

y = 2(-3/5)+2 = 4/5 . . . . for x = -3/5

y = 2(1) +2 = 4 . . . . . . . . for x = 1

The solutions are: (x, y) = (-3/5, 4/5) or (1, 4).

___

A graphing calculator verifies these solutions.

3 0

3 years ago