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telo118 [61]
3 years ago
10

What effect would doubling all the dimensions of a triangular pyramid have on the volume of the pyramid? Explain your reasoning.

Mathematics
2 answers:
Masteriza [31]3 years ago
5 0

Answer:

Hey are you in TTU K-12? I am.

Step-by-step explanation:

spin [16.1K]3 years ago
4 0

Doubling all the dimensions of a triangular pyramid, the volume of the pyramid becomes quadrupled.

Explanation:

The volume of the triangular pyramid is given by

$V_{1}=\frac{1}{3} \cdot b \cdot h$

where b is the base of the pyramid and

h is the height of the pyramid.

Doubling all the dimensions of the pyramid, we have,

b=2b and h=2h

Thus, volume of the triangular pyramid is given by

$V_{2}=\frac{1}{3} \cdot2b \cdot 2h$

Multiplying, we get,

$V_{2}=\frac{1}{3}4bh

$V_{2}=4\frac{1}{3}bh

V_2$=4 \cdot V_{1}$

Thus, doubling all the dimensions of a triangular pyramid, the volume of the pyramid becomes quadrupled.

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Answer:

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Step-by-step explanation:

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A^2   +  B^2  = C^2

^              ^          ^

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first side

Substitute:

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SImplify:

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In the second triangle, we are given 2 sides.

Let's do the same thing we did in the first one.

Givens:

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8^2 + 15^2 = c^2

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Reduce:

289 = c^2

Let's now square root both sides

square root of 289 is 17

so we are left with this:

c=17

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