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LenaWriter [7]
3 years ago
5

A group of 8 friends went to lunch and spent a total of $76, which included the food bill and a tip of $16. They decided to spli

t the bill and tip evenly among themselves.
Which equations and solutions describe the situation? Select two options.
Mathematics
2 answers:
nekit [7.7K]3 years ago
7 0

Answer:

A and C

Step-by-step explanation:

1) The equation 1/8(x+16)=76/8 represents the situation, where x is the food bill.

2) The solution x=60 represents the total food bill.

Kisachek [45]3 years ago
6 0

Answer:

$11.50 is being split among the 8 friends

Step-by-step explanation:

76 + 16 = 92

92/8 = 11.5

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Answer:

i think B

Step-by-step explanation:

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3 years ago
Solve 8w – 3r = 45 for r
bogdanovich [222]
<span>8w – 3r = 45 
3r = 8w - 45
  r = 8w/3 - 15
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3 years ago
The answer to this question please
cestrela7 [59]

If its to number 9, it's ∈35.48

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3 years ago
HELP PLEASE Which expression is equivalent to:
mojhsa [17]

21 V³ 15- 9V³15

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4 0
2 years ago
A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
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