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Oxana [17]
2 years ago
11

Adrian, who weighs 112 lb, held his pet

Mathematics
2 answers:
never [62]2 years ago
7 0
16 ounces also known as a pound. From how I understood it this should be correct!
sergiy2304 [10]2 years ago
4 0

Answer: 1 pound

Step-by-step explanation:

Adrian's weight + dog weight

Minus Adrian's weight

= dog weight

113 - 112 = 1 pound

1 pound or 16 ounces

1lb = 16oz

Hope this helps!!! Good luck!!! ;)

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A heater repairman charges $40 to visit a home, plus $70 per hour for the time he spends on the repair. This situation can be de
frez [133]

Answer:

b = 40

Step-by-step explanation:

A heater repairman charges $40 to visit a home, plus $70 per hour for the time he spends on the repair.

This situation can be described by an equation of the form y=mx+b , where

x = the time in hours

y = the cost in dollars.

What is the value of b in this equation?

A heater repairman charges $40 to visit a home, plus $70 per hour for the time he spends on the repair

Writing the above in an equation =

y = $70 × x + $40

y = 70x + 40

Therefore, the value of b in the expression = 40

3 0
2 years ago
Matt scored 5 runs in each of the 3 baseball games that he had this week. How many runs did Matt score this week?
hram777 [196]
15 because he scores 5 runs I n each of the 3 games he played so you do 5x3=15.
3 0
2 years ago
Need help plz ASAP plz 10 points
satela [25.4K]

Answer:

i think its b

Step-by-step explanation:

5 0
2 years ago
PLZZZZZ HELP ME! :) XDDD
Taya2010 [7]
 In order to figure out what the answer is you would have to divide the number of feet it fell by the time. If you do 35.75 divided by 3.25 it would be 11. 
So the answer most likely would be 11
Please correct me if I am wrong
Have a great day!
4 0
3 years ago
Evaluate the indefinite integral. <br> integar x4/1 + x^10 dx
ivann1987 [24]

Answer:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c

Step-by-step explanation:

Given

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

Required

Integrate

We have:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

Let

u = x^5

Differentiate

\frac{du}{dx} = 5x^4

Make dx the subject

dx = \frac{du}{5x^4}

So, we have:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx

\int\ {\frac{x^4}{1 + x^{10}}} \, \frac{du}{5x^4}

\frac{1}{5} \int\ {\frac{1}{1 + x^{10}}} \, du

Express x^(10) as x^(5*2)

\frac{1}{5} \int\ {\frac{1}{1 + x^{5*2}}} \, du

Rewrite as:

\frac{1}{5} \int\ {\frac{1}{1 + x^{5)^2}}} \, du

Recall that: u = x^5

\frac{1}{5} \int\ {\frac{1}{1 + u^2}}} \, du

Integrate

\frac{1}{5} * \arctan(u) + c

Substitute: u = x^5

\frac{1}{5} * \arctan(x^5) + c

Hence:

\int\ {\frac{x^4}{1 + x^{10}}} \, dx = \frac{1}{5}( \arctan(x^5)) + c

7 0
3 years ago
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