Ask question

Ask question

All categories

Angelina_Jolie [31]

3 years ago

6

What is the equation of the described circle? A) (x − 2)2 + (y + 3)2 = 58 B) (x − 2)2 + (y + 3)2 = 68 Eliminate C) (x + 2)2 + (y

− 3)2 = 58 D) (x + 2)2 + (y − 3)2 = 68

1 answer:

SIZIF [17.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

64

You might be interested in

Plz solve! I need help!

exis [7]

You would want to buy is the One quart if you add up 20.3 + 18.2 you should get is 38.5 subtract that from 50. That's how much paint you would have left over. Hope this helped!

3 0

3 years ago

In a factory a manager tests 250 products and find defcts in 7 of them how many defcts are likely going to be in 10000 unit orde

Kisachek [45]

So first you take 7/250*x/10000 and you cross multiply. Then you get
70000=250x
and the answer is
x=280

I hope this helps!!!!!!!

7 0

3 years ago

What is 664.895 to the nearest tenth

anastassius [24]

The answer would be 664.9 because it would be tenths, hundredth,and then thousandth

6 0

3 years ago

Read 2 more answers

Jessica is eating a bag of sour skittles . Her friend ask her to share, and Jessica throws over an extra bag. Her friend does no

liraira [26]

Answer:

A parabola opens downward with vertex at (1,20)

Step-by-step explanation:

The function that models the height of bag of candies is

$h(t) = - 16 {t}^{2} + 32t + 4$

The graph of this function is a parabola that opens downward.

To find the maximum height of the candy bag, we complete the squares to obtain the vertex form of the function.

Factor -16 to get;

$h(t) = - 16( {t}^{2} - 2t) + 4$

Add and subtract the square of half the coefficient of t.

$h(t) = - 16( {t}^{2} - 2t + 1) + 16+ 4$

Factor the perfect square trinomial:

$h(t) = - 16( {t - 1)}^{2} + 20$

The vertex is (1,20)

This means the maximum height after 1 second is 20 feet.

7 0

3 years ago

Jack and Jim went biking. Jack biked for 5 1/3 hours with average speed 12 1/2 miles per hour. Jim traveled exactly 1 1/5 as far

ahrayia [7]

Given that Jack biked for $5 \frac{1}{3}$ hours with an average speed of $12 \frac{1}{2}$ miles per hour.

The distance travelled by Jack is given by

$d=speed\times time \\ \\ =12 \frac{1}{2}\times5 \frac{1}{3}= \frac{25}{2} \times \frac{16}{3} \\ \\ = \frac{200}{3} =66 \frac{2}{3} \ miles$

Given that Jim travelled exactly $1 \frac{1}{5}$ as far as Jack did, then the distance Jim travelled is given by

$d=1 \frac{1}{5} \times66 \frac{2}{3} \\ \\ = \frac{6}{5} \times \frac{200}{3} =80$

Therefore, the length of Jim's journey is 80 miles.

3 0

3 years ago