All categories

3 years ago

Create sample spaces for a Rhino, Elephant, and Lion. create all as possible. HELP!!!

1 answer:

3 0

There are 6 possibilities.
Rhino, elephant, lion
rhino, lion, elephant
elephant, lion, rhino
elephant, rhino, lion
Lion, rhino, elephant
lion, elephant, rhino

You might be interested in

Which statement about rational numbers is true?

Ilya [14]

Answer:

im not to good at math but im pretty sure that its 1. all rational numbers ae fractions

Step-by-step explanation:

6 0

3 years ago

I need help..................

Angelina_Jolie [31]

1.0 2.39 3.3 4.-17 5.. 15 6. -24 7. 43 8. 39 9. -11 10.-17

5 0

3 years ago

Read 2 more answers

Pitcher holds 65 ounces she drinks 6 cups how much water is left in the pitchet

devlian [24]

There is 17 Ounces left! Or 2.12500 cups.

3 0

3 years ago

Read 2 more answers

The sum of two numbers is 24 and their difference is 2?

mote1985 [20]

X + y = 24
x - y = 2

Adding both equations
2x = 26
x = 13
y = 11

7 0

3 years ago

The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago