What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
Answer:
I've never been to waffle house
Converting 25 degrees to radians:
180° = π radians.
1° = π/180 radians.
25° = (π/180 radians) * 25
= (25/180) * π radians.
Leaving the answer in terms of π, 25/180 = 5/36
= (25/180) * π radians = (5/36)π radians or ≈ 0.1389π radians.
Therefore 25° = (5/36)π radians or ≈ 0.1389π radians
I hope this explains it.
I think why you did not get it was because you did not leave your answer in terms of π or as a multiple of π, so as a multiple of π our answer is:
= (5/36)π radians or ≈ 0.1389π radians
A^2+ b^2= c^2
24^2+b^2=25^2
576+b^2=625
Sub 576
b^2= 49 b=7
