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3 years ago

Help please. Please Please

Mathematics

1 answer:

iragen [17]3 years ago

8 0

$2x - 6 = 60 - x \\ add \: x \: to \:both \: sides \\ 2x + x - 6 = 60 - x + x \\ 3x - 6 = 60 \\ add \: 6 \: to \: both \: sides \\ 3x - 6 + 6 = 60 + 6 \\ 3x = 66 \\ divide \: both \: sides \: by \: 3 \\ \frac{3x}{3} = \frac{66}{3} \\ x = 22$

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Find the value of c that completes the square. k^2-18k+c

eimsori [14]

Answer:

c = 81

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3 years ago

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What are the coordinates of the turning point for the function f(x) = (x - 1)3 - 3? A. (-1, -3)

Naddik [55]

ANSWER

The turning point is

$(1,-3).$

EXPLANATION

The function given to us is

$f(x) = (x - 1) ^{3} - 3$

At turning point,
$f '(x) = 0$

So we need to differentiate the given function and equate it to zero.

We using the chain rule of differentiation, we obtain,
$f '(x) =3 (x - 1) ^{2}$

We equate this to zero to obtain,

$3 (x - 1) ^{2} = 0$

We divide through by 3.

$(x - 1) ^{2} = 0$

We solve for x to get,

$x - 1 = 0$

$x = 1$

We substitute this x-value in to the function to obtain the corresponding y-value of the turning point.

$f(1) = (1- 1) ^{3} - 3$

$f(1) = 0 - 3$

$f(1) = - 3$

Therefore the turning point is

$(1,-3)$

C is the correct answer.

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4 years ago

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Please help solve the ineaquality x over 3 is < than 3

elena55 [62]

We have an inequation:
x/3 < 3
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The final answer is x < 9~

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3 years ago

Whats the lateeal area of length 18, width 13,and 6 hieght

Wewaii [24]

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4 years ago

10. A cylindrical can has a base with a diameter of 6 cm. Its height measures 5 cm. What is the total surface area of the can?

eduard

Answer:

Total surface area of cylinderal can is 150.8 cm²

Step-by-step explanation: 

Given that a cylinderal can has base with a diameter of 6 cm and its height measures 5 cm.

So,

Radius = Diameter/2 = 6/2 = 3 cm

We know that,

TSA of cylinder = 2πr(h + r)

Substituting required values:

➝ TSA = 2 × 22/7 × 3(5 + 3)

➝ TSA = 44/ 7 × 3 × 8

➝ TSA = 1056/7

➝ TSA = 150.8 cm²

Hence,

Total surface area of cylinderal can is 150.8 cm²

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2 years ago

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