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Akimi4 [234]
3 years ago
10

Help please. Please Please

Mathematics
1 answer:
iragen [17]3 years ago
8 0

2x - 6 = 60 - x  \\ add \: x \: to \:both \: sides \\  2x + x - 6 = 60 - x + x \\ 3x - 6 = 60 \\ add \: 6 \: to \: both \: sides \\ 3x - 6 + 6 = 60 + 6 \\ 3x = 66 \\ divide \: both \: sides \: by \: 3 \\  \frac{3x}{3}  =  \frac{66}{3}  \\ x = 22

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2 years ago
I need help please??? ):
andrew11 [14]

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4 0
4 years ago
the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width
-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.  

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}

On solving the above expression for x we get

\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}

\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}

Hence length and width of rectangle is 15 inches and 6 inches.

4 0
4 years ago
Convert the measurement as indicated. 5.2 mi to feet
FrozenT [24]

It would be 27,456 feet


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3 years ago
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3 years ago
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