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aleksklad [387]
3 years ago
14

Find the volume of the solid

Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0
Length times width times height
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Rebecca and dan are biking in a national park for three days they rode 5 3/4 hours the first day and 6 4/5 hours the second day
AfilCa [17]

Answer:

Rebecca and Dan need to ride 7\frac{9}{20}\ hrs. on the third day in order to achieve goal of biking.

Step-by-step explanation:

Given:

Goal of Total number of hours of biking in park =20 hours.

Number of hours rode on first day = 5\frac34 \ hrs.

So we will convert mixed fraction into Improper fraction.

Now we can say that;

To Convert mixed fraction into Improper fraction multiply the whole number part by the fraction's denominator and then add that to the numerator,then write the result on top of the denominator.

5\frac34 \ hrs. can be Rewritten as \frac{23}{4}\ hrs

Number of hours rode on first day = \frac{23}{4}\ hrs

Also Given:

Number of hours rode on second day = 6\frac45 \ hrs

6\frac45 \ hrs can be Rewritten as \frac{34}{5}\ hrs.

Number of hours rode on second day = \frac{34}{5}\ hrs.

We need to find Number of hours she need to ride on third day in order to achieve the goal.

Solution:

Now we can say that;

Number of hours she need to ride on third day can be calculated by subtracting Number of hours rode on first day and Number of hours rode on second day from the Goal of Total number of hours of biking in park.

framing in equation form we get;

Number of hours she need to ride on third day = 20-\frac{23}{4}-\frac{34}{5}

Now we will use LCM to make the denominators common we get;

Number of hours she need to ride on third day = \frac{20\times20}{20}-\frac{23\times5}{4\times5}-\frac{34\times4}{5\times4}= \frac{400}{20}-\frac{115}{20}-\frac{136}{20}

Now denominators are common so we will solve the numerator we get;

Number of hours she need to ride on third day =\frac{400-115-136}{20}=\frac{149}{20}\ hrs \ \ Or \ \ 7\frac{9}{20}\ hrs.

Hence Rebecca and Dan need to ride 7\frac{9}{20}\ hrs. on the third day in order to achieve goal of biking.

3 0
3 years ago
Which graph shows the solution to the system of linear inequalities?<br> y&lt; 2x-5<br> y&gt;-3x + 1
trapecia [35]

Answer:

See explanation

Step-by-step explanation:

Plot the solution sets to both inequalities.

1. For the inequality y First, plot the dotted line y=2x+5 (dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

2\cdot 0-5=-5

so the origin does not belong to the needed part. Shade the part, which does not include origin.

2. For the inequality y>-3x+1. First, plot the dotted line y=-3x+1 (dotted because sign is without notion "or equal to"), then choose correct part by substitution coordinates of the origin.

-3\cdot 0+1=1>0

so the origin does not belong to the needed part. Shade the part, which does not include origin.

3. Find the common region of these two shaded parts - this is the solution to the system of two inequalities.

5 0
3 years ago
Please answer I will be giving out brainliest and 2<br>7 points.​
maria [59]
1. 21 peanuts per minute
2. 9 texts per minute
3. 28 pages per hour OR half a page per minute

4. The first option is the cheapest. You can find what one ounce costs for each barrel by dividing the cost by the total ounces.

6 0
3 years ago
Show tan(???? − ????) = tan(????)−tan(????) / 1+tan(????) tan(????)<br> .
anyanavicka [17]

Answer:

See the proof below

Step-by-step explanation:

For this case we need to proof the following identity:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

We need to begin with the definition of tangent:

tan (x) =\frac{sin(x)}{cos(x)}

So we can replace into our formula and we got:

tan(x-y) = \frac{sin(x-y)}{cos(x-y)}   (1)

We have the following identities useful for this case:

sin(a-b) = sin(a) cos(b) - sin(b) cos(a)

cos(a-b) = cos(a) cos(b) + sin (a) sin(b)

If we apply the identities into our equation (1) we got:

tan(x-y) = \frac{sin(x) cos(y) - sin(y) cos(x)}{sin(x) sin(y) + cos(x) cos(y)}   (2)

Now we can divide the numerator and denominato from expression (2) by \frac{1}{cos(x) cos(y)} and we got this:

tan(x-y) = \frac{\frac{sin(x) cos(y)}{cos(x) cos(y)} - \frac{sin(y) cos(x)}{cos(x) cos(y)}}{\frac{sin(x) sin(y)}{cos(x) cos(y)} +\frac{cos(x) cos(y)}{cos(x) cos(y)}}

And simplifying we got:

tan(x-y) = \frac{tan(x) -tan(y)}{1+ tan(x) tan(y)}

And this identity is satisfied for all:

(x-y) \neq \frac{\pi}{2} +n\pi

8 0
3 years ago
4 Solve the system to find the y-value of the
ser-zykov [4K]

Answer: B

Step-by-step explanation:

7(-2) - 4(1) = -18

-14 - 4 = -18

-18 = -18

TRUE

(-2) + 12(1) = 10

-2 + 12 = 10

10 = 10

TRUE

3 0
3 years ago
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