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3 years ago

Find the volume of the solid

Mathematics

1 answer:

dolphi86 [110]3 years ago

8 0

Length times width times height

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The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=

Leno4ka [110]

1 step: $S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}$ , $S_{3}=T_{1}+T_{2}+T_{3}$ , then
$S_{5}-S_{3}=T_{4}+T_{5}=5$ .

2 step: $T_{n}=T_{1}*q^{n-1}$ , then
$T_{6}=T_{1}*q^{5}$
$T_{5}=T_{1}*q^{4}$
$T_{4}=T_{1}*q^{3}$
$T_{3}=T_{1}*q^{2}$
and $\left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right.$ will have form $\left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right.$ and dividing first equation on second we obtain $\frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}$ . So, $\frac{(q-1)(q+1)}{q+1} = \frac{1}{2}$ and $q-1= \frac{1}{2}$ , $q= \frac{3}{2}$ - the common ratio.

4 step: Insert $q= \frac{3}{2}$ into equation $T_{1}*q^{3}*(q+1)=5$ and obtain $T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5$ , from where $T_{1}= \frac{16}{27}$ .

5 0

3 years ago

Can someone pls help me

jolli1 [7]

Answer:

x=−8 and y=−4

Step-by-step explanation:

8x−17y=4;−8x+15y=4

add eqn1 and 2

to eliminate x

you will get y=-4

put it zin eqn 1

x=-8

8 0

2 years ago

In the multiplication sentence below, which number is the product?

emmasim [6.3K]

Answer:

C. 90

Step-by-step explanation:

The numbers being multiplied are "factors." The result of multiplication is a "product." In this problem, the product is 90.

8 0

2 years ago

(15 Points)

Serga [27]

Not direct answer but

this is how I think

radius = 4 so AC is also 4

You can find with this

2π ( 4 ) ( 51°/360°) = Answer

Actually I am lazy to calculate (◔‿◔)

7 0

3 years ago

Where do y=10x+20 and y=5x+50 intercept

PolarNik [594]

Answer:

(6, 80)

Step-by-step explanation:

First, should mark your y intercepts, which are +20 and +50 on your y axis.

Next, you must know how to use rise over run.

10 = 10/1 and 5 = 5/1

If you have a graph, you can use it for this step:

Next, you rise up 10 then go right 1 because it is positive, and do the same thing over and over again for your first equation. For your next equation, you go up 5 and right 1 since it is also positive.

4 0

3 years ago