Ask question

Ask question

All categories

3 years ago

6

two airplanes leave an airport at the same time and travel in opposite directions. one plane travels 70km/h slower than the othe

r. if the two planes are 5472 km apart after 3 hours what is the rate of each plane

1 answer:

Nitella [24]3 years ago

8 0

Answer:

<em>The speeds are 877 km/h and 947 km/h.</em>

Step-by-step explanation:

The slower plane travels at x km/h. The faster plane travels at (x + 70) km/h. The speed of separation is the sum of the speeds, (2x + 70) km/h.

They are 5472 km after 3 hours of travel.

speed = distance/time

2x + 70 = 5472/3

2x + 70 = 1824

2x = 1754

x = 877

The slower plane travels at 877 km/h.

x + 70 = 877 + 70 = 947

The faster plane travels at 947 km/h.

You might be interested in

Jen and Nikki are making bracelets to sell at the local market. They determined

yulyashka [42]

Answer:

order pair (8,2),

(8,3),

(8,4),

(8,5)

5 0

2 years ago

URGENT Solve 2(4 x + 3) < 5 x + 21. { x | x < 9} { x | x > -5} { x | x > -9} { x | x < 5}

zmey [24]

Answer:

{ x | x < 5}

Step-by-step explanation:

2(4 x + 3) < 5 x + 21

8x + 6 < 5x + 21

3x < 15

x < 5

Answer

{ x | x < 5}

6 0

3 years ago

This is due like right now, please help me!!!!

Varvara68 [4.7K]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given \: Rules}}$

<u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
<u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
<u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

$\bold{\underline{ Let's \: Begin}}$

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>

$\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }$

$\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}$

<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>

$\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}$

$\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}$

<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>

$\sf{ 158 + b = 166 + a, 156 + d = 166 + a }$

$\sf{ b = 166 - 158 + a, d = 166 - 156 + a }$

$\sf{ b = 8 + a, d = 10 + a ...(3)}$

<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{229+a = 161+8+a+c = 168+10+a+e}$

$\sf{ 229+a = 169+a+c = 178+a+e}$

<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>

$\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}$

$\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}$

$\sf{ c = 60 \: and \: e = 51 }$

<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

$\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }$

$\sf{ 158 + b = 156 + d = 166 + a = 189}$

<u>Now</u><u>, </u>

$\sf{ For \: b, 158 + b = 189 }$

$\sf{ b = 189 - 158 }$

$\sf{ b = 31}$

$\sf{ For \: d , 156 + b = 189 }$

$\sf{ d = 189 - 156 }$

$\sf{ d = 33}$

$\sf{ For \: a, 166 + a = 189 }$

$\sf{ a = 189 - 166 }$

$\sf{ a = 23 }$

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

8 0

2 years ago

I really need help pls pls pls help

STatiana [176]

To get how many inches the model is divide by feet per inch
242/22=11
The model in 11 inch long
Should be the first one

8 0

2 years ago

3x-10>4+7x-3<br><br><br> Please explain.

larisa [96]

3x-10>4+7x-3

3x-10>1+7x

-4x-10>1

-4x>11

x<-11/4

Hope Your Thanksgiving Goes Well, Here's A Turkey

-TheKoolKid1O1

7 0

3 years ago

Read 2 more answers