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4vir4ik [10]
3 years ago
6

two airplanes leave an airport at the same time and travel in opposite directions. one plane travels 70km/h slower than the othe

r. if the two planes are 5472 km apart after 3 hours what is the rate of each plane
Mathematics
1 answer:
Nitella [24]3 years ago
8 0

Answer:

<em>The speeds are 877 km/h and 947 km/h.</em>

Step-by-step explanation:

The slower plane travels at x km/h. The faster plane travels at (x + 70) km/h. The speed of separation is the sum of the speeds, (2x + 70) km/h.

They are 5472 km after 3 hours of travel.

speed = distance/time

2x + 70 = 5472/3

2x + 70 = 1824

2x = 1754

x = 877

The slower plane travels at 877 km/h.

x + 70 = 877 + 70 = 947

The faster plane travels at 947 km/h.

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Numa caixa estão berlindes vermelhos,amarelos e azuis: 20%dos berlindes são vermelhos,40% são amarelos e o número de berlindes a
Agata [3.3K]

Answer:

200 berlindes

Step-by-step explanation:

Vamos representar

O número total de berlindes na caixa = X

Mármores vermelhos = 20% de X

= 0.2X

Mármores amarelos = 40% de X

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Conseqüentemente,

0.2X + 0.4X + 80 = X

Recolher termos semelhantes

80 = X - 0.2X - 0.4X

80 = X - 0.6X

80 = 0.4X

Divida ambos os lados por 0.4

X = 80 / 0.4

X = 200

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3 0
3 years ago
Find the value of t, rounded to the nearest tenth
sergij07 [2.7K]

<u>Given</u>:

Given that RST is a right triangle.

The measure of ∠R is 35°.

The length of ST is 12 units.

The length of the hypotenuse is t units.

We need to determine the value of t.

<u>Value of t:</u>

The value of t can be determined using the trigonometric ratio.

Thus, we have;

sin \ \theta=\frac{opp}{hyp}

where \theta=R, the side opposite to ∠R is ST and hypotenuse is SR.

Substituting these values, we get;

sin \ R=\frac{ST}{SR}

Substituting ST = 12 and SR = t, we get;

sin \ 35^{\circ}=\frac{12}{t}

Simplifying, we get;

t=\frac{12}{sin \ 35^{\circ}}

t=\frac{12}{0.574}

t=20.9

Thus, the value of t is 20.9 units.

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1. m= 3/4

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