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4vir4ik [10]
3 years ago
6

two airplanes leave an airport at the same time and travel in opposite directions. one plane travels 70km/h slower than the othe

r. if the two planes are 5472 km apart after 3 hours what is the rate of each plane
Mathematics
1 answer:
Nitella [24]3 years ago
8 0

Answer:

<em>The speeds are 877 km/h and 947 km/h.</em>

Step-by-step explanation:

The slower plane travels at x km/h. The faster plane travels at (x + 70) km/h. The speed of separation is the sum of the speeds, (2x + 70) km/h.

They are 5472 km after 3 hours of travel.

speed = distance/time

2x + 70 = 5472/3

2x + 70 = 1824

2x = 1754

x = 877

The slower plane travels at 877 km/h.

x + 70 = 877 + 70 = 947

The faster plane travels at 947 km/h.

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The width of the rectangle is 1/3 of the length. Find the length and width of the rectangle.
adell [148]

Answer:

1.333333333

Step-by-step explanation:

6 0
3 years ago
Curtis wants to save money for a trip overseas. Curtis invests $900 in an account that pays an interest rate of 8.75%. How many
professor190 [17]
Hi there
The formula is
A=p (1+r)^t
A future value 11700
P present value 900
R interest rate 0.0875
T time?
We need to solve for t
T=log (A/p)÷log (1+r)
So
T=log(11,700÷900)÷log(1+0.0875)
T=30.6years round your answer to get
T=31 years

Hope it helps
7 0
3 years ago
Read 2 more answers
1)Sheyna drive to the lake and back. It took two hours less time to get there than it did to get back. The average speed on the
ipn [44]

Answer:

8 hours

Step-by-step explanation:

Given:

Sheyna drives to the lake with average speed of 60 mph and

v_1 = 60\ mph

Sheyna drives back from the lake with average speed of 36 mph

v_2 = 36\ mph

It took 2 hours less time to get there than it did to get back.

Let t_1 be the time taken to drive to lake.

Let t_2 be the time taken to drive back from lake.

t_2-t_1 = 2 hrs ..... (1)

To find:

Total time taken = ?

t_1+t_2 = ?

Solution:

Let D be the distance to lake.

Formula for time is given as:

Time =\dfrac{Distance}{Speed }

t_1 = \dfrac{D}{60}\ hrs

t_2 = \dfrac{D}{36}\ hrs

Putting in equation (1):

\dfrac{D}{36}-\dfrac{D}{60} = 2\\\Rightarrow \dfrac{5D-3D}{180} = 2\\\Rightarrow \dfrac{2D}{180} = 2\\\Rightarrow D = 180\ miles

So,

t_1 = \dfrac{180}{60}\ hrs = 3 \ hrs

t_2 = \dfrac{180}{36}\ hrs = 5\ hrs

So, the answer is:

t_1+t_2 = \bold{8\ hrs}

8 0
3 years ago
Solving equations 10z+3z+5=2(z-3)
Nesterboy [21]

Answer: Use the PEMDAS rule

Step-by-step explanation: 0z+3z+5=2(z-3)=

z= -1

you need to do the z numbers all together and the normal numbers together then subtract them to get -1

I hope that I help you

5 0
3 years ago
Evaluate the following expression. 5^-3
Ulleksa [173]
5^-3 is 1/125

The negative in the exponent makes it so there is a 1 over the problem if there was no negative. When you have a negative in the exponent, the answer will be the reciprocal (opposite) of the question with no negative.
For example,

9^2 = 81

9^-2 = 1/81

6 0
3 years ago
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