two airplanes leave an airport at the same time and travel in opposite directions. one plane travels 70km/h slower than the othe
r. if the two planes are 5472 km apart after 3 hours what is the rate of each plane
1 answer:
Answer:
<em>The speeds are 877 km/h and 947 km/h.</em>
Step-by-step explanation:
The slower plane travels at x km/h. The faster plane travels at (x + 70) km/h. The speed of separation is the sum of the speeds, (2x + 70) km/h.
They are 5472 km after 3 hours of travel.
speed = distance/time
2x + 70 = 5472/3
2x + 70 = 1824
2x = 1754
x = 877
The slower plane travels at 877 km/h.
x + 70 = 877 + 70 = 947
The faster plane travels at 947 km/h.
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