Answer:
There is no need to make an algorithm for this simple problem. Just add the two numbers by storing in two different variables as follows:
Let a,b be two numbers.
c=a+b;
print(c);
But, if you want to find the sum of more numbers, you can use any loop like for, while or do-while as follows:
Let a be the variable where the input numbers are stored.
while(f==1)
{
printf(“Enter number”);
scanf(“Take number into the variable a”);
sum=sum+a;
printf(“Do you want to enter more numbers? 1 for yes, 0 for no”);
scanf(“Take the input into the variable f”);
}
print(Sum)
Explanation:
hi there answer is given mar me as brainliest
Answer:
year = int(input("Enter a year: "))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print(str(year) + " - leap year")
else:
print(str(year) +" - not a leap year")
else:
print(str(year) + " - leap year")
else:
print(str(year) + "- not a leap year")
Explanation:
*The code is in Python.
Ask the user to enter a year
Check if the <u>year mod 4</u> is 0 or not. If it is not 0, then the year is not a leap year. If it is 0 and if the <u>year mod 100</u> is not 0, then the year is a leap year. If the <u>year mod 100</u> is 0, also check if the <u>year mod 400</u> is 0 or not. If it is 0, then the year is a leap year. Otherwise, the year is not a leap year.
Make the zig zag part more spaced out
Answer:
I’m not sure if you can only teachers can acess that
Explanation:
Answer:
it would have to be flow control which would be C.
Explanation:
