The answer is already given at the end of the question; solely by the magnitude or severity of expected harm
When assessing risks of harm associated with participation in a research study, the probability of harm and the risk of the severity of harm are two distinctive elements of risk that must be considered. In probability of harm, the fact that not all possible harms are equally probable should be considered. How these two elements occur is a crucial factor in determining the level of risk of harm in a study. Given the sensitivity of the information in the case scenario above, the probability that an individual subject could be identified is low while the magnitude of the possible risk of harm is high.
Answer:
Hi there! This can be implemented in a simple Python function which uses the "random" module to generate the number.
Explanation:
Using Python as the languge, we can write a the below code in a file called styles.py. The first line imports the randint function from the "random" module. The setStyles() function declares an array or 5 elements (here I have just used numbers but these could be string names of the stylesheets as well). Next, styleNum is assigned the random number and the associated stylesheet is selected from the array of stylesheets.
styles.py
from random import randint
def setStyles():
stylesheets = [1,2,3,4,5];
styleNum = randint(1,5);
stylesheet = stylesheets[styleNum];
print(stylesheet);
setStyles();
Answer:
There is no short answer.
Explanation:
First let's create the string:
- alphabetString = "abcdefghijklmnopqrstuvwxyz";
The first half of the string using slice method can be written as:
- alphabetString.slice(0, 13);
The first half of the string using only the ending index can be written as:
- alphabetString.slice(-13);
When we put - at the start of the index number, the counting begins at the last element with -1 and goes backwards.
The second half of the string can be written as:
- alphabetString.slice(13,26);
The second half of the string using only the starting index can be written as:
- alphabetString.slice(13);
To get the every second letter in the string, we need a for loop:
- for( let x = 0; x < alphabetString.length(); x = x + 2){
alphabetString.slice(x);
}
To get the entire string in reverse, we can use the reverse method that is built-in:
- alphabetString.reverse();
To get the every third letter of the string, we can again use a for loop:
- for( let x = -1; x = -27; x = x - 3){
alphabetString.slice(x);
}
I hope this answer helps.
