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densk [106]
3 years ago
15

Find t12 for a geometric sequence where t1=2+2i and r=3

Mathematics
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

T_{12} = 354294 + 354294i

Step-by-step explanation:

Given

Geometric Sequence (GP)

T_1 = 2 + 2i

r = 3

Required

Determine T₁₂

The nth term of a GP is calculated as thus;

T_n = ar^{n-1}

In this case;

n = 12;  r = 3 and a = T_1 = 2 + 2i

Substitute these values in the above formula

T_{12} = (2 + 2i) * 3^{12-1}

T_{12} = (2 + 2i) * 3^{11}

T_{12} = (2 + 2i) * 177147

Open the bracket

T_{12} = 177147 * 2 + 177147 * 2i

T_{12} = 354294 + 354294i

<em>Hence, the 12th term of the sequence is </em>T_{12} = 354294 + 354294i

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Answer:

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Step-by-step explanation:

12u and -uv both have a factor of <em>u </em>in common, so we can pull it out to give us the factored expression u(12-v).

<em>Note on factoring:</em>

<em>Remember, it's just using the distributive property in reverse! We can get our original expression back by distributing the u to the 12 and the -v.</em>

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3 years ago
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lana [24]
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3 0
4 years ago
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andriy [413]

Answer:

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Step-by-step explanation:

Length = 18 in

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V = 540 in³

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Rashid [163]

Answer:

C

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