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3 years ago

Write the equation of the line, in point-slope form. Identify (x, y) as the point (-2, 2). Use the box provided or the upload

Mathematics

1 answer:

Bingel [31]3 years ago

3 0

Answer:

y = -x + 0

Step-by-step explanation:

well the equation of a line is y = mx + b

m = the slope , b = the y-intercept

m = y2 - y1 / x2 - x1

m = -1

and b is the y-intercept of the line.

finally:

y = -1x + 0

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What is the value of 6n-2

ad-work [718]

Factor 6n−2
6n−2
=2(3n−1)
Answer: 2(3n−1)

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3 years ago

Find the solutions of the form x=a,y=0and x=0 ,y=b for the following equations: 2x+5y=10 and 2x+3y=6. is there any common soluti

Arlecino [84]

Answer:

x=0 and y=2

Step-by-step explanation:

We have been given system of equations:

2x+5y=10 (1)

And 2x+3y=6 (2)

Subtract equation (2) from(1) we get:

2y=4

y=2

Now, substitute y=2 in equation(2) we get:

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Hence, x=0 and y=2

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3 years ago

White raven [17]

The ratio of the volume of pipe a to the volume of pipe b is 27:1 .

<h3>What is cylinder?</h3>

A cylinder is a three-dimensional shape consisting of two parallel circular bases, joined by a curved surface. The center of the circular bases overlaps each other to form a right cylinder.

Given that,

Radius of pipe a is 6 cm, and the radius of pipe b is 2 cm.

We know that the volume of cylinder is :- $\pi r^{2}h$

where r is radius and h is height of the cylinder.

If two figures are similar then ratio of volume is equal to the cube of any dimension.

The ratio of the volume of Pipe a to the volume of Pipe b :-

$\frac{V(a)}{V(b)}=\frac{6^{3} }{2^{3} }$

= $\frac{27}{1}$

Hence, The ratio of the volume of pipe a to the volume of pipe b is 27:1 .

To learn more about cylinder from the given link:

brainly.com/question/1392572

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1 year ago

How many times do 14 go into 50

masha68 [24]

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3 years ago

Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.

Blizzard [7]

Answer:

The answer is

$y = 3$

$y = - 4$

Step-by-step explanation:

We must find a solution where

$\frac{6}{y + 1} + \frac{y}{y - 2} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

$\frac{6}{y + 1} \times \frac{y - 2}{y - 2} + \frac{y}{y - 2} \times \frac{y + 1}{y + 1}$

Which equals

$\frac{6y - 12}{(y -2) (y + 1)} + \frac{ {y}^{2} + y }{(y - 2)(y + 1)}$

Add the fractions

$\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)} = \frac{6}{y + 1} \times \frac{y}{y - 2}$

Simplify the right side by multiplying the fraction

$\frac{6y}{(y + 1)(y + 2)}$

Set both fractions equal to each other

$\frac{6y}{(y + 1)(y - 2)} = \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}$

Since the denomiator are equal, we must set the numerator equal to each other

$6y = {y}^{2} + 7y - 12$

$= {y}^{2} + y - 12$

$(y + 4)(y - 3)$

$y = - 4$

$y = 3$

6 0

3 years ago

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