The total amount accrued, principal plus interest, with compound interest on a principal of $1,000.00 at a rate of 3% per year compounded 12 times per year over 0.5 years is $1,015.09.
<h3>Compound Interest</h3>
Given Data
- Time = 6 months = 0.5 years
First, convert R as a percent to r as a decimal
r = R/100
r = 3/100
r = 0.03 rate per year,
Then solve the equation for A
A = P(1 + r/n)^nt
A = 1,000.00(1 + 0.03/12)^(12)(0.5)
A = 1,000.00(1 + 0.0025)^(6)
A = $1,015.09
Learn more about compound interest here:
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Answer:
y = (1/3)x - 9
Step-by-step explanation:
We know that m = 1/3
The function will be in the form:
y = (1/3)x + b
Let's find b by plugging in the coordinates of the point, in the function:
-7 = (1/3)*6 + b
b = -9
Therefore:
y = (1/6)x - 9
Answer:
Step-by-step explanation:
cotx/cscx=cosx
Start on the left side.
cos(x) csc(x)
Apply the reciprocal identity to csc (x) .
cos(x) 1/sin(x)
Simplify
cos(x) 1/sin(x)cos(x)/sin(x)
Rewrite cos(x)/sin(x) as cot(x) .
cot(x)
Because the two sides have been shown to be equivalent, the equation is an identity.
cos(x) csc(x)=cot(x) is an identity
cot(x)−tan(x)/sin(x)cos(x)=csc^2(x)−sec^2(x) is an identity
You are correct :)
<h2>
Answer:</h2>
Luke does a work of 308Nm
<h2>
Step-by-step explanation:</h2>
If we have a constant force 
that acts on a body in the same direction as the displacement 
, then the work 
is defined as the product of the force magnitude 
and the displacement magnitude 
. In other words:
, which is valid for a constant force in direction of straight-line displacement.
In this problem:
Therefore:
Answer:
this is as test
Step-by-step explanation:
