Question

You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length. Suppose that the perimeter of a rectangle is 34 feet, and the length is 7 feet more than the width. Find the width of the rectangle, in fee

Answer 1

Answer:

5 feet

Step-by-step explanation:

P = 2(w + l)

P = 34

l = w + 7

34 = 2 (w + w + 7)

34 = 2w + 2w + 14

34 - 14 = 4w

20 = 4w

w = 5 feet

Since l = w + 7

l = 5 + 7

l = 12 feet