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Leokris [45]
3 years ago
5

Please help!!!!!!!!!!!!!!!!!!!!!

Computers and Technology
1 answer:
Aloiza [94]3 years ago
4 0
1.
#include <iostream>#include <string>
using namespace std;
int main(){    string chars; // This is where we will put our @ signs and print them    for(int x=0;x < 5; x++){
        chars = chars + '@'; // This will concatenate an @ sign at the end of the variable        cout << chars << "\n";    }}

2.
#include <iostream>#include <string>
using namespace std;
int main(){    string name; // Our variable to store the name    cout << "What is your name? \n"; // Asks the user for their name    cin >> name;    cout << "\nWell, hello " << name << "!";}

3.
#include <iostream>#include <string>
using namespace std;
int main(){    int number; // Our variable    cout << "Enter a number\n"; // Asks for a number    cin >> number;    cout << "You entered " << number << "%!";}

4.
#include <iostream>#include <string>
using namespace std;
int main(){    int number; // Our variable    cout << "Enter a number\n";    cin >> number;
    int check = number % 2; // The modulo operator (the percent sign) gets the remainder of the quotient    if (check == 0) {        cout << number << " is even!"; // If the remainder is 0 then it prints out "x is even"    } else {        cout << number << " is odd!"; // If the remainder is not 0 then it prints out "x is odd"    }}

5.
#include <iostream>#include <string>
using namespace std;
int main(){    float r; // Our variable    cout << "Enter a radius\n";    cin >> r;    if (r < 0){        cout << "Lol. No."; // If the radius is less than zero print out that message    }    float circumference=2*3.14*r;    float area=r*r*3.14;    cout << "\n\n Circumference of circle: " << circumference;    cout << "\n Area of circle: " << area;}
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Using the knowledge in computational language in python it is possible to write a code that computes an integer's checksum.

<h3>Writting the code:</h3>

<em>def checkSum(n):                    # Function definition</em>

<em>    total = 0                       # total variable which returns sum</em>

<em>    c = 0                           # counter variable which count the even position</em>

<em>    while(n!=0):                    # running a loop while n != 0</em>

<em>        r = int(n%10)               #breaking the number into digits</em>

<em>        c=c+1                       # increase counter</em>

<em>        if c%2==0:                  # if counter is even position then double the number </em>

<em>            r = r*2</em>

<em>            while(r!=0):                            # do the process</em>

<em>                total = total + int(r%10)</em>

<em>                r = int(r/10)</em>

<em>            n=int(n/10)    </em>

<em>        else:                       # if counter is odd position then simple add the digit </em>

<em>            total = total + r       # into total</em>

<em>            n=int(n/10)</em>

<em>    return total                    # in the last return the sum of digits</em>

<em># Driver code</em>

<em>n = int(input("Enter Number:"))         # asking user to enter the number </em>

<em>print(checkSum(n))                      # calling the function</em>

See more about python at brainly.com/question/18502436

#SPJ1

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