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4 years ago

How to chnage email adresss on slate from tophat?

Computers and Technology

1 answer:

padilas [110]4 years ago

6 0

Answer:

First visit the Tophat website on https://tophatblue.com.

To access and manage your Slate account on Slate:

Log in to the server with your username and password. Click your profile picture or your initials and select My Account and then select Profile.

Under the profile, you will see the following profile information: You can verify and edit them.

- Name

- Username

- Email

- Set a new password

To verify or edit your email address, click Email.

Upon verification of your email by the Slate server, a check appears alongside it.

Should you need another verification email, select the Verify email option.

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Write, compile, and test the MovieQuoteInfo class so that it displays your favorite movie quote, the movie it comes from, the ch

Irina18 [472]

Using the knowledge of computational language in JAVA it is possible to write a code that removes your favorite phrase from the movie. It consists of two classes in which one is driver code to test the MovieQuoteInfo class.

<h3>Writing code in JAVA:</h3>

public class MovieQuoteInfo { //definition of MovieQuoteInfo class

//All the instance variables marked as private

private String quote;

private String saidBy;

private String movieName;

private int year;

public MovieQuoteInfo(String quote, String saidBy, String movieName, int year) { //parameterized constructor

super();

this.quote = quote;

this.saidBy = saidBy;

this.movieName = movieName;

this.year = year;

}

//getters and setters

public String getQuote() {

return quote;

}

public void setQuote(String quote) {

this.quote = quote;

}

public String getSaidBy() {

return saidBy;

}

public void setSaidBy(String saidBy) {

this.saidBy = saidBy;

}

public String getMovieName() {

return movieName;

}

public void setMovieName(String movieName) {

this.movieName = movieName;

}

public int getYear() {

return year;

}

public void setYear(int year) {

this.year = year;

}

//overriden toString() to print the formatted data

public String toString() {

String s = quote+",\n";

s+="said by "+this.saidBy+"\n";

s+="in the movie "+this.movieName+"\n";

s+="in "+this.year+".";

return s;

}

}

Driver.java

public class Driver { //driver code to test the MovieQuoteInfo class

public static void main(String[] args) {

MovieQuoteInfo quote1 = new MovieQuoteInfo("Rosebud", "Charles Foster Kane", "Citizen Kane", 1941);//Create an object of MovieQuoteInfo class

System.out.println(quote1); //print its details

}

}

See more about JAVA at brainly.com/question/12975450

#SPJ1

7 0

2 years ago

Write two methods: encrypt and decrypt. encrypt should #take as input a string, and return an encrypted version #of it according

Harman [31]

Answer:

The code is given below with appropriate comments

Explanation:

CIPHER = (("D", "A", "V", "I", "O"),

("Y", "N", "E", "R", "B"),

("C", "F", "G", "H", "K"),

("L", "M", "P", "Q", "S"),

("T", "U", "W", "X", "Z"))

# Add your code here!

def encrypt(plaintext):

theList = []

for char in plaintext:

if char.isalpha():

char = char.upper()

if char == "J":

char = "I"

theList.append(char)

if len(theList) % 2 == 1:

theList.append("X")

for i in range(0, len(theList), 2):

if theList[i] == theList[i + 1]:

theList[i + 1] = "X"

findex = [-1, -1]

sindex = [-1, -1]

for j in range(len(CIPHER)):

for k in range(len(CIPHER)):

if theList[i] == CIPHER[j][k]:

findex = [j, k]

if theList[i + 1] == CIPHER[j][k]:

sindex = [j, k]

# same row

if (findex[0] == sindex[0]):

findex[1] += 1

sindex[1] += 1

if findex[1] == 5:

findex[1] = 0

if sindex[1] == 5:

sindex[1] = 0

theList[i] = CIPHER[findex[0]][findex[1]]

theList[i + 1] = CIPHER[sindex[0]][sindex[1]]

# same column

elif (findex[1] == sindex[1]):

findex[0] += 1

sindex[0] += 1

if findex[0] == 5:

findex[0] = 0

if sindex[0] == 5:

sindex[0] = 0

theList[i] = CIPHER[findex[0]][findex[1]]

theList[i + 1] = CIPHER[sindex[0]][sindex[1]]

else:

theList[i] = CIPHER[findex[0]][sindex[1]]

theList[i + 1] = CIPHER[sindex[0]][findex[1]]

return "".join(theList)

def decrypt(ciphertext):

theString = ""

findex = [-1, -1]

sindex = [-1, -1]

for i in range(0, len(ciphertext), 2):

for j in range(len(CIPHER)):

for k in range(len(CIPHER)):

if ciphertext[i] == CIPHER[j][k]:

findex = [j, k]

if ciphertext[i + 1] == CIPHER[j][k]:

sindex = [j, k]

if (findex[0] == sindex[0]):

findex[1] -= 1

sindex[1] -= 1

if findex[1] == -1:

findex[1] = 4

if sindex[1] == -1:

sindex[1] = 4

theString += CIPHER[findex[0]][findex[1]]

theString += CIPHER[sindex[0]][sindex[1]]

# same column

elif (findex[1] == sindex[1]):

findex[0] -= 1

sindex[0] -= 1

if findex[0] == -1:

findex[0] = 4

if sindex[0] == -1:

sindex[0] = 4

theString += CIPHER[findex[0]][findex[1]]

theString += CIPHER[sindex[0]][sindex[1]]

else:

theString += CIPHER[findex[0]][sindex[1]]

theString += CIPHER[sindex[0]][findex[1]]

return theString

# Below are some lines of code that will test your function.

# You can change the value of the variable(s) to test your

# function with different inputs.

# If your function works correctly, this will originally

# print: QLGRQTVZIBTYQZ, then PSHELXOWORLDSX

print(encrypt("PS. Hello, worlds"))

print(decrypt("QLGRQTVZIBTYQZ"))

5 0

3 years ago

Fill in the blank with the correct response.

SCORPION-xisa [38]

Higher Resolution i guess it depends on what it’s requiring

3 0

3 years ago

Suppose that the five measured SampleRTT values are 106 ms, 120 ms, 140 ms, 90 ms, and 115 ms.

jeyben [28]

Answer:

a) 100.75, 103.15, 107.756, 105.536, 106.72

b) 5.06, 8, 14.061, 14.43, 12.89

Explanation:

Measured sample RTT values : 106 ms, 120 ms, 140 ms, 90 ms, 115 ms

First estimated RTT value = 100 ms

∝ = 0.125

β = 0.25

First DevRTT value = 5 ms

A) Compute the EstimatedRTT after each of these SampleRTT values is obtained,

Formula for estimated RTT = ( 1 - ∝ ) . estimated RTT + ∝.sample RTT

B). Compute the DevRTT after each sample is obtained,

Formula for DevRTT = ( 1 - β ) . DevRTT + β. | sample RTT - Estimated RTT |

attached below is a detailed solution

5 0

3 years ago

Is a web-based architectural approach in which users interact via a web browser or other web-enabled view layer with application

katrin2010 [14]

Hi,

Yes to include real-time interaction between users on website you need more than just raw HTML and CSS. You would need functionality so include JS or .NET framework (C# or VB), you could also add Python, but most of all in order to control user information: Database.

Hope this helps.
r3t40

7 0

3 years ago