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pav-90 [236]
3 years ago
9

Help me with #20, please

Mathematics
2 answers:
Fed [463]3 years ago
8 0
Flour is 3 because 3x3=9 and 3x6 is half of 3 =18 and sugar is 18 count by 9's
eduard3 years ago
3 0
In the flour row it is 4.5 and in the sugar row it is 18. Hope this helps :)
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for each of the following find, if possible, a whole number that makes the equation true. a. 3+ z=12 b. 36 = 18 + 3 •Z
Basile [38]

Answer:

a. 9

b. 6

Step-by-step explanation:

a. z=12 - 3= 9

b. (36 - 18)/3= Z

6 0
3 years ago
How do I put the slope and y-intercept on the graph
mestny [16]
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Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
4. (03.03 HC)
Kitty [74]

Answer:

A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones

Step-by-step explanation:

B. table : (8,8)(12,12)(14,16)(16,16)

               look at ur points...when x = 8, y = 8...so the table, when x = 8 has a

               value of 8

relation : f(x) = 8x - 5....when x = 8

             f(8) = 8(8) - 5

             f(8) = 64 - 5

             f(8) = 59....and the relation has a value of 59

Therefore, the relation has a greater value when x = 8 <==

C. f(x) = 8x - 5...when f(x) = 19

    19 = 8x - 5

     19 + 5 = 8x

    24 = 8x

    24/8 = x

    3 = x <==

7 0
3 years ago
14. What is the reflection image of (5, -3) across the line y = -x? (3, -5) (3, 5) (-3, 5) (-3, -5)
Nata [24]

Answer:

The reflection image of (5, -3) across the line y = -x is (3, -5).

Step-by-step explanation:

You can find the reflection equation by putting the value of x and y in the line given one by one.

5 0
3 years ago
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