Answer:
1.f(x)=2x-5
i will take the set {-2,-1,0,1,2}
f(-2)=2(-2)-5
=-4-5
=-9
f(-1)=2(-1)-5
=-2-5
=-7
f(0)=2(0)-5
=-5
f(1)=2(1)-5
=-3
f(2)=2(2)-5
=-1
so the coordinates of the function is {-9,-7,-5,-3,-1}
2.f(x)=-3x+6
i will the take the set {-2,-1,0,1,2} too
f(-2)=-3(-2)+6=6+6=12
f(-1)=-3(-1)+6=3+6=9
f(0)=-3(0)+6=6
f(1)=-3(1)+6=-3+6=3
f(2)=-3(2)+6=-6+6=0
{12,9,6,3,0}
3.f(x)=2/3.x+4
{-2,-1,0,1,2}
f(-2)=2/3(-2)+4=-4/3+4=(-4+12)/3=8/3
f(-1)=2/3(-1)+4=-2/3+4=(-2+12)/3=10/3
f(0)=2/3(0)+4=4
f(1)=2/3(1)+4=2/3+4=(2+12)/3=14/3
f(2)=2/3(2)+4=4/3+4=(4+12)/3=16/3
{8/3,10/3,4,14/3,16/3}
you're can graph those coordinates
actually you can take other coordinates...
CMIIW
,
Answer:
y - 5 = -4(x + 3)
Step-by-step explanation:
This question is asking you to use and make an equation using the base of the "point-slope form." This is a common equation used when dealing with coordinates and graphs in math. The point-slope form equation looks like this:
y - y₁ = m(x - x₁).
We are going to need to use this equation base to create our problem from the information given. If you are wondering what those subscripts of 1 mean (the 1 in y₁ and x₁), I will explain. Remember that:
slope (m) = <u>y - y₁</u>
x - x₁
So, our first y value (which is the y-coordinate of 5 in [-3, 5]) can be added into the problem base that I had mentioned above:
y - <u>5</u> = m(x - x₁).
Now, we need to place the first x value (which is the -3 in [-3, 5]) can be added into the base problem once more:
y - 5 = m(x - (<u>-3</u>)).
Because a negative number with a negative symbol in front of it creates a positive, we can change that as well:
y - 5 = m(x + 3).
Fortunately, the question provides a slope ready for use. The question says that the slope is -4, so we can place this into the equation now:
y - 5 = -4(x + 3).
I hope that this helps.
18/35 is halfway between 3/5 and 5/7. Do you want me to explain or just the answer?
Since these are parabolas with y being squared, the standard form of such a parabola with vertex at (h, k) is
<span>x = a(y - k)^2 + h </span>
<span>There are no steps. Just look at what is inside the parentheses and compare it to (y - k) with k = -3. </span>
<span>Then look at what is added and compare it to h = -1. </span>
<span>For instance, A has (y + 1) in parentheses. So k = -1. And it has -3 added, so h = -3. That would be a vertex at (-3, -1).</span>
