Question

Emil's backpack weighs six and three eights pounds. He removes a book that weighs three fourth pound. Then he removes a book that weighs one half pound .How much does Emil's back pack weigh now

Answer 1

Answer:

Emil's back pack weigh now $5\frac{1}{8}\ pounds$.

Step-by-step explanation:

Given:

Total Weight of backpack = $6\frac{3}{8}\ pounds$

$6\frac{3}{8}\ pounds$ can be Rewritten as $\frac{51}{8}\ pounds$

Weight of backpack =  $\frac{51}{8}\ pounds$

Weight of Book 1 = $\frac{3}{4}\ pound$

Weight of Book 2 = $\frac{1}{2}\ pound$

We need to find weight of back pack after removing books.

Solution:

Now we can say that;

weight of back pack after removing books can be calculated by Subtracting Weight of Book 1 and Weight of Book 2 from Total Weight of backpack.

framing in equation form we get;

weight of back pack after removing books = $\frac{51}{8}-\frac{3}{4}-\frac{1}{2}$

Now to solve the equation we will first make the denominator common using LCM.

weight of back pack after removing books =$\frac{51\times1}{8\times1}-\frac{3\times2}{4\times2}-\frac{1\times4}{2\times4}=\frac{51}{8}-\frac{6}{8}-\frac{4}{8}$

Now the denominators are common so we will solve the numerator.

weight of back pack after removing books = $\frac{51-6-4}{8}=\frac{41}{8}\ pounds \ \ OR \ \ 5\frac{1}{8}\ pounds$

Hence Emil's back pack weigh now $5\frac{1}{8}\ pounds$.