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Georgia [21]
3 years ago
8

To insure QoS of a network, an alternative to “prioritizing traffic” is to __________, which means holding back traffic from non

-time sensitive apps so that apps like voice and video run more effectively. Select one:
Computers and Technology
1 answer:
Lemur [1.5K]3 years ago
6 0

Answer: Throttle traffic

Explanation:

Throttle traffic insures to increase or decrease the traffic so as to improve the QoS of a network. It allows holding back traffic from non-time sensitive apps so that apps like voice and video run more effectively

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Answer:

False

Explanation:

Without any police, a privacy can easily be compromised.

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4 years ago
What is the easiest way to beat all of the fnaf games without getting killed and beating all of the nights?
MrRa [10]

Answer:

If you want the game to be "hard" be paranoid. If you are not scared, this game is simple. All you have to do is check your camera to pirate's cove to see if foxy is there. Otherwise, check the halls on your left and right. When Bonnie and/or Chica come, quickly close your doors and wait till they go away. Then, on night five, check the stage to make sure freddy has not moved. Night 5+ is the only real challenge.

Explanation:

My Strategy

Rythm is essential to surviving all the nights at Freddy Fazbears. Here is what I do.

First, check the light on the left.

If anyone is there close the door, or keep the door shut

If not, or after you have closed the door, move on to the next step.

Then, close the right door*.

Check the camera to make sure foxy has not moved.

If Foxy has moved, quickly shut the right door and check camera 2A. When your are pulled out of your camera, return to your camera and check on Foxy.

Check the right hall light.

If anyone is there close the door, or keep the door shut.

If no one is there, or you have the door shut, repeat all of these steps

5 0
3 years ago
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A spreadsheet will complete a variety of mathematical formulas for the user.<br><br> True or false
Lady bird [3.3K]

Answer: True

Explanation:

A spreadsheet will complete any formula as long as its entered by the user

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Data Structure in C++
agasfer [191]

The code .cpp is available bellow

#include<iostream>

using namespace std;

//declaring variables

void merge(int* ip, int sz, int* opt, bool opt_asc); //merging

int* mergesort(int* ip, int sz);

void mergesort(int *ip, int sz, int* opt, bool opt_asc);

void merge(int* ip, int sz, int* opt, bool opt_asc)

{

  int s1 = 0;

  int mid_sz = sz / 2;

  int s2 = mid_sz;

  int e2 = sz;

  int s3 = 0;

  int end3 = sz;

  int i, j;

   

  if (opt_asc==true)

  {

      i = s1;

      j = e2 - 1;

      while (i < mid_sz && j >= s2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (i != mid_sz)

      {

          while (i < mid_sz)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (j >= s2)

      {

          while (j >= s2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

      }

  }

  else

  {

      i = mid_sz - 1;

      j = s2;

      while (i >= s1 && j <e2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

      if (i >= s1)

      {

          while (i >= s1)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

      }

      if (j != e2)

      {

          while (j < e2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

  }

   

  for (i = 0; i < sz; i++)

      *(ip + i) = *(opt + i);

}

int* mergesort(int* ip, int sz)

{

  int* opt = new int[sz];

   

  mergesort(ip, sz, opt, true);

  return opt;

}

void mergesort(int *ip, int sz, int* opt, bool opt_asc)

{

  if (sz > 1)

  {

      int q = sz / 2;

      mergesort(ip, sz / 2, opt, true);

      mergesort(ip + sz / 2, sz - sz / 2, opt + sz / 2, false);

      merge(ip, sz, opt, opt_asc);

  }

}

int main()

{

  int arr1[12] = { 5, 6, 9, 8,25,36, 3, 2, 5, 16, 87, 12 };

  int arr2[14] = { 2, 3, 4, 5, 1, 20,15,30, 2, 3, 4, 6, 9,12 };

  int arr3[10] = { 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 };

  int *opt;

  cout << "Arays after sorting:\n";

  cout << "Array 1 : ";

  opt = mergesort(arr1, 12);

  for (int i = 0; i < 12; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 2 : ";

  opt = mergesort(arr2, 14);

  for (int i = 0; i < 14; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 3 : ";

  opt = mergesort(arr3, 10);

  for (int i = 0; i < 10; i++)

      cout << opt[i] << " ";

  cout << endl;

  return 0;

}

4 0
4 years ago
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