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Natasha_Volkova [10]
3 years ago
11

Fragmentation can lead to a dataset which is too large for maximum supported size of a communication container, such as a segmen

t, packet, or frame. The original dataset divides into multiple sections or fragments for transmission across the size-limited medium, and then reassembles on the receiving end.
A. True
B. False
Computers and Technology
1 answer:
Masja [62]3 years ago
3 0

Answer:

True

Explanation:

As the name implies, fragmentation is simply to divide datasets into smaller fragments. When a data is too large to the extent that it has maxed the supported size of a communication container such as disk, packet, frame, or segment, the dataset is divided into various fragments in order for the communication container to access or read the information, and then it reassembles the dataset back on the receiving end.

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Which of the following would be the most appropriate way to address and greet your teacher, Mr. Joseph Herman, in an email? Hi J
Valentin [98]
To determine what would be the most appropriate way to address and greet your teacher during an email, we should eliminate some greetings, such as:
"Yo wassup?", "How  u doin?", or any other grammatical and socially inappropriate errors.
Let's look at our first option.
"Hi Joseph, How u doin??". This is incorrect as it is not appropriate to address anyone in such a manner and with grammatical errors.
Let's look at our second option.
"Dear Joseph Herman, how are you doing!!". This was on the right path, but didn't end well. The ending of the message, "how are you doing!!" is incorrect punctuation, and has too much excitement.
How about our third option?
"Dear Mr. Herman, I hope you're doing fine.". This is a great email. It has perfect punctuation, grammar, and is appropriate.
What about our fourth?
"Dear Joseph, i hope you are doing great.". This is a good email, but has incorrect punctuation.
Your answer is C.) Dear Mr. Herman, I hope you're doing fine.
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3 years ago
Match the context details with the pattern that applies.
tia_tia [17]

Answer:

1. - Observer

2. - iterator

3. - strategy

4. - composite

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Explanation:

An object contains other objects (elements) and must give access to them for clients, without exposing its internal structure. This is an observation.

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What is a recent technological breakthrough with an impact that can be compared to the invention of paper nearly 2,000 years ago
Evgesh-ka [11]
<span>Electronic communication</span>
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3 years ago
Read 2 more answers
What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C
Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80                                    

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100  -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70   -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice)  -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice  -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice  -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref)  -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80  -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20  -> This line adds 20 to the value of Cost  and assigns the result to Cost variable

End Subprogram  -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e.  Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80                              

7 0
3 years ago
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