Question

The function h(x) = –x5 + 12x is an odd function. Which transformation of h(x) results in an odd function? A.h(5 – x) B.1 + h(x) C.h(x + 8) D.–6h(x)

Answer 1

Answer:

$\Huge \boxed{\mathrm{B.} \ 1+h(x)}$

$\rule[225]{225}{2}$

Step-by-step explanation:

The function is odd when f(-x) = -f(x).

1 + h(-x) = 1 + -h(x)

$1 + -(-x)^5 + 12(-x) = 1 + -(-x^5 + 12x)$

Solving:

$1 + x^5 -12x= 1 + x^5 - 12x$

$x=x$

The equation is true.

$\rule[225]{225}{2}$

Answer 2

$\huge\underline{\underline{\mathfrak{\red{A}\green{n}\pink{s}\orange{w}\blue{e}{r}}}}$

$B. \:1 \:+ \:h(x)$