Answer: The value of a is 1. The value of b is -1. The value of c is 1. The value of the discriminant is -3. The quadratic function will not intersects the x-axis.

Explanation:

The standard form of a quadratic equation is,

$p(x)=ax^2+bx+c$

The given function is,

$p(x)=x(x-1)+1$

It can be written as,

$p(x)=x^2-x+1$

By comparing this equation with the standard form of quadratic equation. we get,

$a=1$

$b=-1$

$c=1$

The formula for discriminant is,

$D=b^2-4ac$

$D=(-1)^2-4(1)(1)$

$D=1-4$

$D=-3$

The value of the discriminant is -3.

If D<0, it means the function have no real roots.

If D=0, it means function have one real roots.

If D>0, it means function have two real roots.

Since D<0 it means the function have no real roots. So the function will not intersect the x-axis at any point.

8 0

4 years ago

Read 2 more answers

4. Identify whether each function is linear or non-linear. Then, evaluate the function for the given value of

ozzi

$f(x) = x3 + 2x2 + 6 \\ f(3) = (3)3 + 2(3)2 + 6 \\ = 9 + 12 + 6 \\ f(3) = 28 \\ \\ f(x) = 1x \\ f(8) = 1(8) \\ = 8 \\ f(8) = 8$

6 0

3 years ago