let's change some the 0.1 to say 1/10, just the fraction version of it.
![\bf \cfrac{-10x-1}{-10x^3-x^2}\implies \cfrac{-10\left( \frac{1}{10} \right)-1}{-10\left( \frac{1}{10} \right)^3-\left( \frac{1}{10} \right)^2}\implies \cfrac{-1-1}{-\frac{1}{100}-\frac{1}{100}}\implies \cfrac{-2}{\frac{-2}{100}} \\\\\\ \cfrac{~~\begin{matrix} -2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{1}\cdot \cfrac{100}{~~\begin{matrix} -2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 100](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B-10x-1%7D%7B-10x%5E3-x%5E2%7D%5Cimplies%20%5Ccfrac%7B-10%5Cleft%28%20%5Cfrac%7B1%7D%7B10%7D%20%5Cright%29-1%7D%7B-10%5Cleft%28%20%5Cfrac%7B1%7D%7B10%7D%20%5Cright%29%5E3-%5Cleft%28%20%5Cfrac%7B1%7D%7B10%7D%20%5Cright%29%5E2%7D%5Cimplies%20%5Ccfrac%7B-1-1%7D%7B-%5Cfrac%7B1%7D%7B100%7D-%5Cfrac%7B1%7D%7B100%7D%7D%5Cimplies%20%5Ccfrac%7B-2%7D%7B%5Cfrac%7B-2%7D%7B100%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B~~%5Cbegin%7Bmatrix%7D%20-2%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7B1%7D%5Ccdot%20%5Ccfrac%7B100%7D%7B~~%5Cbegin%7Bmatrix%7D%20-2%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%5Cimplies%20100)
when checking an absolute value expression, we do the one-sided limits, since an absolute value expression is in effect a piecewise function with ± versions, so for the limit from the left we check the negative version.
Answer:
<em>The perimeter is 72 units and the area is 149 square units.</em>
Step-by-step explanation:
has coordinates 
and 
Using the distance formula.........
Length of side 
Length of side 
Length of side 
So, the perimeter of the triangle will be: 
units. <em>(Rounded to the nearest unit)</em>
The height of the triangle for the corresponding base 
is 8.89 units.
<u>Formula for the Area of triangle</u>, 
So, the area of the will be: 
square units. <em>(Rounded to the nearest unit)</em>
Answer: C.
Step-by-step explanation: Plug in x in the formula. Solve for each y by plugging in each x in the formula and seeing if it works. This took me like 3 min to solve
The measure of ∠7 is 47°. Angle 7 is a vertical angle to angle 5
Suppose the measure of ∠6 is represented represented by (2x - 5), the equation that can be use to solve for x is 42 + 2x = 180
The value of x is 69
<h3>Vertical opposite angles</h3>
Vertically opposite angles are angles that are opposite one another at a specific vertex and are created by two straight intersecting lines.
Vertical opposite angles are congruent. Therefore,
a. ∠5 ≅ ∠7 (vertical angles)
Therefore, angles 5 and 7 are congruent angles.
∠7 = 47°
b. Suppose ∠6 = 2x - 5 . let's find x
Therefore,
∠5 + ∠6 = 180(angle on a straight line)
The equation to solve the above is as follows:
47 + 2x - 5 = 180
42 + 2x = 180
2x = 180 - 42
2x = 138
x = 138 / 2
x = 69
learn more on intersecting lines here: brainly.com/question/24715845
Answer:
The point-slope form of this equation would be y + 3 = 1/2(x - 6)
Step-by-step explanation:
In order to find this, start with the base form of point-slope form.
y - y1 = m(x - x1)
Now input the slope for m and the point for (x1, y1)
y - -3 = 1/2(x - 6)
y + 3 = 1/2(x - 6)
