Answer:
68% of jazz CDs play between 45 and 59 minutes.
Step-by-step explanation:
<u>The correct question is:</u> The playing time X of jazz CDs has the normal distribution with mean 52 and standard deviation 7; N(52, 7).
According to the 68-95-99.7 rule, what percentage of jazz CDs play between 45 and 59 minutes?
Let X = <u>playing time of jazz CDs</u>
SO, X ~ Normal(
)
The z-score probability distribution for the normal distribution is given by;
Z =
~ N(0,1)
Now, according to the 68-95-99.7 rule, it is stated that;
- 68% of the data values lie within one standard deviation points from the mean.
- 95% of the data values lie within two standard deviation points from the mean.
- 99.7% of the data values lie within three standard deviation points from the mean.
Here, we have to find the percentage of jazz CDs play between 45 and 59 minutes;
For 45 minutes, z-score is =
= -1
For 59 minutes, z-score is =
= 1
This means that our data values lie within 1 standard deviation points, so it is stated that 68% of jazz CDs play between 45 and 59 minutes.
I hope this helps you
(-2/4+3/4).1/5
1/4.1/5
1/20
Answer:
the answer is 309 r 15
Step-by-step explanation:
309 × 27 is 8343 and your left with 15
The answer would be positive 5
Answer:
a.p→¬q
b.¬p→¬q
c.q→¬p
Step-by-step explanation:
p:You drive over 65 miles per hour
¬p: <em>You do not drive over 65 miles per hour</em>
q:You get a speeding ticket
¬q:<em>You do not get a speeding ticket</em>
(a) You drive over 65 miles per hour, but <em>you do not get a speeding ticket</em>
the first sentence is p and because the consequence is the opposite of q then is no q
p→¬q
(b) If you do not drive over 65 miles per hour, then you will not get a speeding ticket
The first sentence is the opposite of p (¬p), and the second sentence is the opposite of q
¬p→¬q
(c) You get a speeding ticket, but you did not drive over 65 miles per hour.
The first one is q, and the second one is the opposite of p so
q→¬p