What is 88 % of 9000?
2 answers:
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Answer:
Step-by-step explanation:
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Answer:
The 90% confidence interval for the mean test score is between 77.29 and 85.71.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 25 - 1 = 24
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.064
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29
The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.
The 90% confidence interval for the mean test score is between 77.29 and 85.71.
Answer:
see explanation
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Subtract the sum of the given angles from 180 for A
A = 180° - (90 + 48)° = 180° - 138° = 42°
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tan48° = =
Multiply both sides by a
a × tan48° = 18 ( divide both sides by tan48° )
a = ≈ 16.2 ( to the nearest tenth )
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sin48° = =
Multiply both sides by c
c × sin48° = 18 ( divide both sides by sin48° )
c = ≈ 24.2 ( to the nearest tenth )